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  • SBI PO Exam Quantitative Aptitude Study Material

Digitization help student to explore and study their academic courses online, as this gives them flexibility and scheduling their learning at their convenience. Kidsfront has prepared unique course material of Quantitative Aptitude Number Series for SBI PO Exam student. This free online Quantitative Aptitude study material for SBI PO Exam will help students in learning and doing practice on Number Series topic of SBI PO Exam Quantitative Aptitude. The study material on Number Series, help SBI PO Exam Quantitative Aptitude students to learn every aspect of Number Series and prepare themselves for exams by doing online test exercise for Number Series, as their study progresses in class. Kidsfront provide unique pattern of learning Quantitative Aptitude with free online comprehensive study material and loads of SBI PO Exam Quantitative Aptitude Number Series exercise prepared by the highly professionals team. Students can understand Number Series concept easily and consolidate their learning by doing practice test on Number Series regularly till they excel in Quantitative Aptitude Number Series.


Number Series
Find two mean proportionals between 2 and 54

a) 6 and 18
b) 6 and 12
c) 12 and 18
d) 6 and 9



Answer
Solution
Correct Answer Is : 6 and 18
Solution Is : Average age of 7 children = 12 years.
Therefore, Excess of average age than the age of child died
= 12 - 6. = 6 years.
Therefore, Increase in ages of the remaining 6 children = 6/6 = 1 years
Therefore, ages of remaining 6 children = 12 + 1 = 13 years.
A sum of 300 is divided among P, Q and R in such a way that Q gets 30 more than P and R gets 60 more than g. The ratio of their share is

a) 5 : 3 : 2
b) 2 : 3 : 5
c) 3 : 2 : 5
d) 2 : 5 : 3



Answer
Solution
Correct Answer Is : 2 : 3 : 5
Solution Is : (2) Q=P+30⇒Q-P=30 and
R-Q=60=2*30
Required ratio=2:3:5
Look: 3-2=1,5-3=2
Mohan gets 3 marks for each correct sum and loses 2 marks for each wrong sum. He attempts 30 sums and obtains 40 marks. The number of sums solved correctly is :

a) 15
b) 20
c) 25
d) 10



Answer
Solution
Correct Answer Is : 20
Solution Is :
A man invested 1/3 of his capital at 7%, 1/4 at 8% and the remainder at 10%. If his annual income is Rs. 561, the capital is

a) Rs. 5400
b) Rs. 6000
c) Rs. 6600
d) Rs. 7200



Answer
Solution
Correct Answer Is : Rs. 6600
Solution Is :
And a,b,c are rational numbers,Then a+b+c is equal to

a) 0
b) 1
c) 2
d) 3



Answer
Solution
Correct Answer Is : 0
Solution Is :
An employer reduces the number of employees in the ratio 8 : 5 and increases their wages in the ratio 7 : 9. As a result, the overall wages bill is

a) Increased in the ratio 56 : 69
b) Decreased in the ratio 56 : 45
c) Increased in the ratio 13 : 17
d) Decreased in the ratio 17 : 13



Answer
Solution
Correct Answer Is : Decreased in the ratio 56 : 45
Solution Is : Required ratio = 8*7 : 5*9 =56:45
If the ratio of areas of two similar triangles is 9 : 16, then the ratio of their corresponding sides is

a) 3 : 5
b) 3 : 4
c) 4 : 5
d) 4 : 3



Answer
Solution
Correct Answer Is : 3 : 4
Solution Is :
465 coins consists of 1 rupee, 50 paise and 25 paise coins. Their values are in the ratio 5 : 3 : 1. The number of each type of coins respectively is,

a) 155, 186, 124
b) 154, 187, 124
c) 154, 185, 126
d) 150, 140, 175



Answer
Solution
Correct Answer Is : 155, 186, 124
Solution Is :
The cost of a piece of diamond varies with the square of its weight. A diamond of Rs. 5,184 value is cut into 3 pieces whose weights are in the ratio 1 : 2 : 3. Find the loss involved in the cutting.

a) Rs. 3,068
b) Rs. 3,088
c) Rs. 3,175
d) Rs. 3,168



Answer
Solution
Correct Answer Is : Rs. 3,168
Solution Is : If the weight of a piece of diamond be 6x units, then Original price a(6x)2=36kx2
Therefore 36kx2=5184 ….(i)
Again, New price
=k(x2+4x2+9x2)=14kx2
=(14*5184)/36 =Rs.2016
Therefore, Loss= 5184-2016 =Rs.3168
The L.C.M. of three different numbers is 120.Which of the following cannot be their H.C.F.?

a) 8
b) 12
c) 24
d) 35



Answer
Solution
Correct Answer Is : 35
Solution Is : LCM = 2 x 2 x 2 x 3 x 5 Hence, HCF = 4, 8 or 12
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