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Digitization help student to explore and study their academic courses online, as this gives them flexibility and scheduling their learning at their convenience. Kidsfront has prepared unique course material of Quantitative Aptitude Mixture And Allegation for SBI PO Exam student. This free online Quantitative Aptitude study material for SBI PO Exam will help students in learning and doing practice on Mixture And Allegation topic of SBI PO Exam Quantitative Aptitude. The study material on Mixture And Allegation, help SBI PO Exam Quantitative Aptitude students to learn every aspect of Mixture And Allegation and prepare themselves for exams by doing online test exercise for Mixture And Allegation, as their study progresses in class. Kidsfront provide unique pattern of learning Quantitative Aptitude with free online comprehensive study material and loads of SBI PO Exam Quantitative Aptitude Mixture And Allegation exercise prepared by the highly professionals team. Students can understand Mixture And Allegation concept easily and consolidate their learning by doing practice test on Mixture And Allegation regularly till they excel in Quantitative Aptitude Mixture And Allegation.


Mixture And Allegation
Three tankers contain 403 litres, 434 litres, 465 litres of diesel respectively. Then the maximum capacity of a container that can measure the diesel of the three containers exact number of times is

a) 31 litres
b) 62 litres
c) 41 litres
d) 84 litres



Answer
Solution
Correct Answer Is : 31 litres
Solution Is : Great capacity of measuring vessel = HCF of 403 litres, 434 litres and 465 litres = 31 litres
In a miXture of syrup and water there is 60 per cent syrup. If 5 litres of syrup is added then there is 35 per cent water in the miXture, The initial quantity of miXture was

a) 40 litres
b) 35 litres
c) 30 litres
d) 32 litres



Answer
Solution
Correct Answer Is : 35 litres
Solution Is : Original quantity of miXture = 5X litres syrup = 3X litres; water = 2X litres on adding 5 litres of syrup, percentage of water =2X/5X+5 X 100 2X/5X + 5 X 100 = 35 => 2X/5X + 5 X 20 = 7 => 40X = 35X + 35 5X = 35 X = 7 Original quantity of miXture = 5 X 7 = 35 litres
Two alloys contain tin and iron in the ratio of 1 : 2 and 2 : 3. If the two alloys are mixed in the proportion of 3 : 4 respectively (by weight), the ratio of tin and iron in the newly formed alloy is :

a) 10 : 21
b) 13 : 22
c) 14 : 25
d) 12 : 23



Answer
Solution
Correct Answer Is : 13 : 22
Solution Is : Let 3kg of first alloy and
4kg of second alloy could be mixed together.
Therefore, In 3kg of mixture,
Tin = 1kg
Iron = 2kg.
In 4kg of mixture,
Tin=(2/5)×4 = 8/5 kg=1.6kg
Iron=(3/5)×4=12/5=2.4kg
Therefore,Required ratio
=(1+1.6) : (2+2.4) =2.6 : 4.4
13 : 22
A container has 80 L of milk. From this container 8 L of milk was taken out and replaced by water. The process was further repeated twice. The volue of milk in the container after that is :

a) 85.32 L
b) 58.23 L
c) 85.23 L
d) 58.32 L



Answer
Solution
Correct Answer Is : 58.32 L
Solution Is :
The ratio of the quantities of an acid and water in a mixture is 1 : 3. If 5 litres of acid is further added to the mixture, the new ratio becomes 1 : 2. The quantity of new mixture in litres is

a) 32
b) 40
c) 42
d) 45



Answer
Solution
Correct Answer Is : 45
Solution Is : Let the quantity of acid in original mixture be x litre and that of water be 3x litre.
(x+5)/3x=1/2
=>2x+10=3x
=>x=10
Therefore, quantity of new mixture
=4x+5=45litres.
The ratio of the volumes of water and glycerine in 240cc of a mixture is 1 : 3. The quantity of water (in cc) that should be added to the mixture so that the new ratio of the volume of water and glycerine becomes 2:3 is

a) 55
b) 60
c) 62.5
d) 64



Answer
Solution
Correct Answer Is : 60
Solution Is : In the original mixture,
water = 60 cc
Glycerine = 180 cc
Let x cc of water be mixed.
Therefore (60+x)/180 = 2/3.
==> 180+3x =360
⇒3x= 360 -180 = 180
Hence x=180/3 = 60 cc
729 ml of a mixture contains milk and water in the ratio 7 : 2. How much more water is to be added to get a new mixture containing milk and water in the ratio 7 : 3 ?

a) 60 ml
b) 71 ml
c) 52 ml
d) 81 ml



Answer
Solution
Correct Answer Is : 81 ml
Solution Is : Quantity of milk =(7/9) *729 =567ml
Quantity of water =(2/9)*729 =162ml
Let `x` be the quantity that should be added to make the ratio 7:3.
According to the question, 567/(162+x) =7/3
=>1701 =1134+7x
=> 7x =1701 -1134
=>x=81ml
A shopkeeper bought 30 kg of rice at the rate of Rs. 70 per kg and 20 kg of rice at the rate of Rs. 70.75 per kg. If he mixed the two brands of rice and sold the mixture at Rs. 80.50 per kg, his gain is

a) Rs. 510
b) Rs. 525
c) Rs. 485
d) Rs. 450



Answer
Solution
Correct Answer Is : Rs. 510
Solution Is :
In what ration must 25% of alcohol be mixed with 50% of alcohol to get a mixture of 40% strent alcohol?

a) 1 : 2
b) 2 : 1
c) 2 : 3
d) 3 : 2



Answer
Solution
Correct Answer Is : 2 : 3
Solution Is : Alcohol + alcohol = alcohol
0.25x + 0.50y = 0.40(x+y)
25x + 50y = 40x + 40y
15x = 10y
x:y = 10:15 = 4:3
Amt of 25% is to Amt of 50% as 2 is to 3.
A vessel contains a mixture of milk and water in the respective ratio of 10 : 3. Twenty-six litre of this mixture was taken out and replaced with 8 litre of water. If the resultant respective ratio of ratio of milk and water in the mixture was 5 : 2, what was the initial quantity of mixture in the vessel ? (in litre)

a) 143
b) 182
c) 169
d) 130



Answer
Solution
Correct Answer Is : 130
Solution Is :

Preparation for Exams

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