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SSC CHSL Exam SSC CHSL Quantative Aptitude Study Material

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Algebra

If the length of a rectangle in increased by 20% and width is decreased by 20%, then the area of the rectangle

a) Decreases by 20%
b) Decreases by 4%
c) Increases by 20%
d) Remains unchanged

✔Answer

✔Solution

Correct Answer Is : Decreases by 4%

Solution Is : (B) If the length of a rectangle in increased by 20% and width is decreased by 20%, then the area of the rectangle decreases by 4%

If n and p are both odd numbers, then which of the following is an even number?

a) Np
b) Np+2
c) N+p+1
d) N+p

✔Answer

✔Solution

Correct Answer Is : N+p

Solution Is : (D) If n and p are both odd numbers, then If n+p is an even number.

Given that `a` is less than `b`, then which of the following is greater than `a` and less than `b`?

a) B² - a²
b) (a+b) /2
c) Ab
d) (a+b) / 2

✔Answer

✔Solution

Correct Answer Is : (a+b) / 2

Solution Is : (D) (a+b) / 2 is the correct answer.

For integer n, if n^3 is odd, then which of the following statements are true?
I) n is odd
II) n² is odd
III) n² is even

a) I only
b) II only
c) I & III only
d) I and II only

✔Answer

✔Solution

Correct Answer Is : I and II only

Solution Is : (D) For integer n, if n^3 is odd, n is odd and n² is odd are true.

If the radius of a circle is increased by 6%, then its area is increased by

a) 0.36%
b) 12.36%
c) 36%
d) 3.60%

✔Answer

✔Solution

Correct Answer Is : 12.36%

Solution Is : (B) If radius of the circle = 100 units, = πr²=π?1000 sq units. If radius of the circle becomes 106 units, then area becomes π?π?106?106=11236 sq units π sq units. Therefore percent increase in area =(1236/10000)*100 =12.36

If a/3 = b/2 , then value of (2a+3b)/(3a-2b) is

a) 12/5
b) 5/12
c) 1
d) 12/7

✔Answer

✔Solution

Correct Answer Is : 12/5

Solution Is : Suppose, a = 3k and b = 2k then , ( 23k + 32k) / ( 33k - 22k ) = 12k / 5k = 12 / 5

a)
b)
c)
d)

✔Answer

✔Solution

Correct Answer Is :

Solution Is :

Measure of each interior angle of a regular polygon can never be

a) 150°
b) 105°
c) 108°
d) 144°

✔Answer

✔Solution

Correct Answer Is : 105°

Solution Is : Measure of each interior angle of a regular polygon can never be in odd digit i.e., 105°

a) -1
b) 0
c) 1
d) 1/√3

✔Answer

✔Solution

Correct Answer Is : 0

Solution Is :

a) 3
b) 2
c) 0
d) 1

✔Answer

✔Solution

SSC CHSL Exam SSC CHSL Quantative Aptitude Study Material

Algebra

If the length of a rectangle in increased by 20% and width is decreased by 20%, then the area of the rectangle

Correct Answer Is : Decreases by 4%

Solution Is : (B) If the length of a rectangle in increased by 20% and width is decreased by 20%, then the area of the rectangle decreases by 4%

If n and p are both odd numbers, then which of the following is an even number?

Correct Answer Is : N+p

Solution Is : (D) If n and p are both odd numbers, then If n+p is an even number.

Given that `a` is less than `b`, then which of the following is greater than `a` and less than `b`?

Correct Answer Is : (a+b) / 2

Solution Is : (D) (a+b) / 2 is the correct answer.

For integer n, if n^3 is odd, then which of the following statements are true? I) n is odd II) n2 is odd III) n2 is even

Correct Answer Is : I and II only

Solution Is : (D) For integer n, if n^3 is odd, n is odd and n2 is odd are true.

If the radius of a circle is increased by 6%, then its area is increased by

Correct Answer Is : 12.36%

Solution Is : (B) If radius of the circle = 100 units, = πr2=π?1000 sq units. If radius of the circle becomes 106 units, then area becomes π?π?106?106=11236 sq units π sq units. Therefore percent increase in area =(1236/10000)*100 =12.36

If a/3 = b/2 , then value of (2a+3b)/(3a-2b) is

Correct Answer Is : 12/5

Solution Is : Suppose, a = 3k and b = 2k then , ( 2*3k + 3*2k) / ( 3*3k - 2*2k ) = 12k / 5k = 12 / 5

Correct Answer Is :

Solution Is :

Measure of each interior angle of a regular polygon can never be

Correct Answer Is : 105°

Solution Is : Measure of each interior angle of a regular polygon can never be in odd digit i.e., 105°

Correct Answer Is : 0

Solution Is :

Correct Answer Is : 0

Solution Is :

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For integer n, if n^3 is odd, then which of the following statements are true?
I) n is odd
II) n² is odd
III) n² is even

Solution Is : (D) For integer n, if n^3 is odd, n is odd and n² is odd are true.

Solution Is : (B) If radius of the circle = 100 units, = πr²=π?1000 sq units. If radius of the circle becomes 106 units, then area becomes π?π?106?106=11236 sq units π sq units. Therefore percent increase in area =(1236/10000)*100 =12.36

Solution Is : Suppose, a = 3k and b = 2k then , ( 23k + 32k) / ( 33k - 22k ) = 12k / 5k = 12 / 5