Learn Last Year Paper RRB NTPC 2011 Asm ASM sep 11 paper, RRB NTPC Exam Last Year Paper RRB NTPC 2011 Asm ASM sep 11 paper Exercise, Free Online ASM sep 11 paper Lessons

RRB NTPC Exam Last Year Paper RRB NTPC 2011 Asm Study Material

Digitization help student to explore and study their academic courses online, as this gives them flexibility and scheduling their learning at their convenience. Kidsfront has prepared unique course material of Last Year Paper RRB NTPC 2011 Asm ASM sep 11 paper for RRB NTPC Exam student. This free online Last Year Paper RRB NTPC 2011 Asm study material for RRB NTPC Exam will help students in learning and doing practice on ASM sep 11 paper topic of RRB NTPC Exam Last Year Paper RRB NTPC 2011 Asm. The study material on ASM sep 11 paper, help RRB NTPC Exam Last Year Paper RRB NTPC 2011 Asm students to learn every aspect of ASM sep 11 paper and prepare themselves for exams by doing online test exercise for ASM sep 11 paper, as their study progresses in class. Kidsfront provide unique pattern of learning Last Year Paper RRB NTPC 2011 Asm with free online comprehensive study material and loads of RRB NTPC Exam Last Year Paper RRB NTPC 2011 Asm ASM sep 11 paper exercise prepared by the highly professionals team. Students can understand ASM sep 11 paper concept easily and consolidate their learning by doing practice test on ASM sep 11 paper regularly till they excel in Last Year Paper RRB NTPC 2011 Asm ASM sep 11 paper.

ASM sep 11 paper

Numerical Ability

A trader told his servant Shambhu that he left for his home from the shop after every 2:40 hours. I left for home 55 minutes earlier and for the next time I will leave for home from my shop at 8:5 p.m. At which time did I inform my servant?

a) 6:30
b) 6:00
c) 6:15
d) 4:20

✔Answer

✔Solution

Correct Answer Is : 6:30

Solution Is : The trader Left for his home from the shop for every 2.40 hour. Given, for the next time he will leave for home is 8:15 pm. Hence the previous time he left for home is 8:15 p.m. - 2.40 hrs. =5.35pm Hence the time at which he informed his servant is =5.35 pm + 55 mins =6.30 p.m

Numerical Ability

If the numbers divisible by 3 between 14 and 55 (both inclusive) and the numbers with 3 at unit`s place of them are removed then how may numbers will remain?

a) 24
b) 23
c) 22
d) 25

✔Answer

✔Solution

Correct Answer Is : 25

Solution Is : The number between 14 and 55 (both inclusive) are 14,15,16,17______.53,54,55 Total numbers = 55-13 = 42 The no`s divisible by 3 are 15,18,21,24,27,30,33,36,39,42,45,48,51,54 Total numbers = 14 Ans = 42-(14+4-1) =42-17 =25

Numerical Ability

If X means - , / means + , + means / , - means x them fine the value of 13-12/400+20*100

a) 1/760
b) 76
c) 176
d) 186

✔Answer

✔Solution

Correct Answer Is : 76

Solution Is : By the given condition 13-12/400+20100 can be written as 1312+400/20-100 156+20-100 =76

Numerical Ability

Nivedita stops to walk after covering a distance of 10 km to the west. She then turns to the right and walks 8km. Again she walks 4 km to the right. How far is she from her office?

a) 18 km
b) 8 km
c) 16 km
d) 10 km

✔Answer

✔Solution

Correct Answer Is : 10 km

Solution Is :

Numerical Ability

Karishma is taller than Kajal. Kajal is taller than Vimal. Ankita is taller than Kajan and Vimal. Which is the tallest?

a) Karishma
b) Kajal
c) Ankita
d) None of these

✔Answer

✔Solution

Correct Answer Is : None of these

Solution Is : Let us denote taller using > symbol Karishma > Kajal > Vimal Ankita > Kajal > and Vimal Here the data is inadequate Ans : None of these

Numerical Ability

Radha and Saroj are ranked 10th and 16th respectively in a class of 37 students. What will be their ranks from the bottom in the class?

a) 28th, 22nd
b) 27th, 21st
c) 28th, 20th
d) 27th, 22nd

✔Answer

✔Solution

Correct Answer Is : 28th, 22nd

Solution Is : Total number of students in the class = 37 The rank of Radha and Saroj are 10th and 16th respectively. Hence their ranks from the bottom in the class are 28th (37-9) and 22nd (37-15) in the class

Numerical Ability

If `A` = 26, and SUN = 27, then CAT ?

a) 24
b) 57
c) 58
d) 27

✔Answer

✔Solution

Correct Answer Is : 57

Solution Is : Given A=26 and SUN=27(S=8, U=6, N=13 SUN=8+6+13=27) Hence B=25, C=24,X=3, Y=2, Z=1 CAT= 24+26+7=57

Numerical Ability

A number when divided by three consecutive number 9, 11, 13 leaves the remainders 8, 9 and 8 respectively. If the order of divisions is revered, the remainders will be---

a) 8, 9, 8
b) 9, 8, 8
c) 10, 1, 6
d) 10, 8, 9

✔Answer

✔Solution

Correct Answer Is : 8, 9, 8

Solution Is : Since the number to be divided is same the reminders will be in the reverse order of 8, 9, 8

Numerical Ability

Find the multiple of 11 in the following numbers ?

a) 978626
b) 112144
c) 447355
d) 869756

✔Answer

✔Solution

Correct Answer Is : 978626

Solution Is :

Numerical Ability

Find prime numbers are arranged in ascending order. The product of first three is 385 and that of last three is 1001.The largest prime number is---

a) 11
b) 13
c) 17
d) 9

✔Answer

✔Solution

RRB NTPC Exam Last Year Paper RRB NTPC 2011 Asm Study Material

ASM sep 11 paper

Numerical AbilityA trader told his servant Shambhu that he left for his home from the shop after every 2:40 hours. I left for home 55 minutes earlier and for the next time I will leave for home from my shop at 8:5 p.m. At which time did I inform my servant?

Correct Answer Is : 6:30

Solution Is : The trader Left for his home from the shop for every 2.40 hour. Given, for the next time he will leave for home is 8:15 pm. Hence the previous time he left for home is 8:15 p.m. - 2.40 hrs. =5.35pm Hence the time at which he informed his servant is =5.35 pm + 55 mins =6.30 p.m

Numerical AbilityIf the numbers divisible by 3 between 14 and 55 (both inclusive) and the numbers with 3 at unit`s place of them are removed then how may numbers will remain?

Correct Answer Is : 25

Solution Is : The number between 14 and 55 (both inclusive) are 14,15,16,17______.53,54,55 Total numbers = 55-13 = 42 The no`s divisible by 3 are 15,18,21,24,27,30,33,36,39,42,45,48,51,54 Total numbers = 14 Ans = 42-(14+4-1) =42-17 =25

Numerical AbilityIf X means - , / means + , + means / , - means x them fine the value of 13-12/400+20*100

Correct Answer Is : 76

Solution Is : By the given condition 13-12/400+20*100 can be written as 13*12+400/20-100 156+20-100 =76

Numerical AbilityNivedita stops to walk after covering a distance of 10 km to the west. She then turns to the right and walks 8km. Again she walks 4 km to the right. How far is she from her office?

Correct Answer Is : 10 km

Solution Is :

Numerical AbilityKarishma is taller than Kajal. Kajal is taller than Vimal. Ankita is taller than Kajan and Vimal. Which is the tallest?

Correct Answer Is : None of these

Solution Is : Let us denote taller using > symbol Karishma > Kajal > Vimal Ankita > Kajal > and Vimal Here the data is inadequate Ans : None of these

Numerical AbilityRadha and Saroj are ranked 10th and 16th respectively in a class of 37 students. What will be their ranks from the bottom in the class?

Correct Answer Is : 28th, 22nd

Solution Is : Total number of students in the class = 37 The rank of Radha and Saroj are 10th and 16th respectively. Hence their ranks from the bottom in the class are 28th (37-9) and 22nd (37-15) in the class

Numerical AbilityIf `A` = 26, and SUN = 27, then CAT ?

Correct Answer Is : 57

Solution Is : Given A=26 and SUN=27(S=8, U=6, N=13 SUN=8+6+13=27) Hence B=25, C=24,X=3, Y=2, Z=1 CAT= 24+26+7=57

Numerical AbilityA number when divided by three consecutive number 9, 11, 13 leaves the remainders 8, 9 and 8 respectively. If the order of divisions is revered, the remainders will be---

Correct Answer Is : 8, 9, 8

Solution Is : Since the number to be divided is same the reminders will be in the reverse order of 8, 9, 8

Numerical AbilityFind the multiple of 11 in the following numbers ?

Correct Answer Is : 978626

Solution Is :

Numerical AbilityFind prime numbers are arranged in ascending order. The product of first three is 385 and that of last three is 1001.The largest prime number is---

Correct Answer Is : 13

Solution Is : 385 =5*7*11 1001=7*11*13 Hence the four prime numbers are 5,7,11,13 The largest prime numbers is 13

Kids Learning

Academics

Competitive Exams

Govt. Jobs Exams

Numerical Ability

A trader told his servant Shambhu that he left for his home from the shop after every 2:40 hours. I left for home 55 minutes earlier and for the next time I will leave for home from my shop at 8:5 p.m. At which time did I inform my servant?

Numerical Ability

If the numbers divisible by 3 between 14 and 55 (both inclusive) and the numbers with 3 at unit`s place of them are removed then how may numbers will remain?

Numerical Ability

If X means - , / means + , + means / , - means x them fine the value of 13-12/400+20*100

Solution Is : By the given condition 13-12/400+20100 can be written as 1312+400/20-100 156+20-100 =76

Numerical Ability

Nivedita stops to walk after covering a distance of 10 km to the west. She then turns to the right and walks 8km. Again she walks 4 km to the right. How far is she from her office?

Numerical Ability

Karishma is taller than Kajal. Kajal is taller than Vimal. Ankita is taller than Kajan and Vimal. Which is the tallest?

Numerical Ability

Radha and Saroj are ranked 10th and 16th respectively in a class of 37 students. What will be their ranks from the bottom in the class?

Numerical Ability

If `A` = 26, and SUN = 27, then CAT ?

Numerical Ability

A number when divided by three consecutive number 9, 11, 13 leaves the remainders 8, 9 and 8 respectively. If the order of divisions is revered, the remainders will be---

Numerical Ability

Find the multiple of 11 in the following numbers ?

Numerical Ability

Find prime numbers are arranged in ascending order. The product of first three is 385 and that of last three is 1001.The largest prime number is---

Solution Is : 385 =5711 1001=71113 Hence the four prime numbers are 5,7,11,13 The largest prime numbers is 13