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  • RRB NTPC Exam Last Year Paper RRB NTPC 2011 Asm Study Material

Digitization help student to explore and study their academic courses online, as this gives them flexibility and scheduling their learning at their convenience. Kidsfront has prepared unique course material of Last Year Paper RRB NTPC 2011 Asm ASM sep 11 paper for RRB NTPC Exam student. This free online Last Year Paper RRB NTPC 2011 Asm study material for RRB NTPC Exam will help students in learning and doing practice on ASM sep 11 paper topic of RRB NTPC Exam Last Year Paper RRB NTPC 2011 Asm. The study material on ASM sep 11 paper, help RRB NTPC Exam Last Year Paper RRB NTPC 2011 Asm students to learn every aspect of ASM sep 11 paper and prepare themselves for exams by doing online test exercise for ASM sep 11 paper, as their study progresses in class. Kidsfront provide unique pattern of learning Last Year Paper RRB NTPC 2011 Asm with free online comprehensive study material and loads of RRB NTPC Exam Last Year Paper RRB NTPC 2011 Asm ASM sep 11 paper exercise prepared by the highly professionals team. Students can understand ASM sep 11 paper concept easily and consolidate their learning by doing practice test on ASM sep 11 paper regularly till they excel in Last Year Paper RRB NTPC 2011 Asm ASM sep 11 paper.


ASM sep 11 paper
Numerical Ability

On dividing a number by 19, the difference between quotient and remainder is 9 . The number is --

a) 370
b) 352
c) 361
d)



✔Answer
✔Solution
Correct Answer Is :
Solution Is : When 371 is divided by 19 Quotient = 19 remainder = 10 Hence the difference Quotient remainder =19-10=9 The number is 371
Numerical Ability

Mohan engaged a servant on the condition that he would pay him ? 200 and a uniform after 10 days. The servant served only for 5 days and got ? 20 and a uniform. Find the price of the uniform.

a) ? 80
b) ? 120
c) ? 140
d) ? 160


✔Answer
✔Solution
Correct Answer Is : ? 160
Solution Is :
Numerical Ability

If you subtract -1 from +1, What will be the result?

a) 2
b) -2
c) 0
d) 1


✔Answer
✔Solution
Correct Answer Is : 2
Solution Is : (+1)-(-1)=(+1)+(+1)=2
Numerical Ability

Find the value of 50*8

a) 40
b) 200
c) 8
d) 0


✔Answer
✔Solution
Correct Answer Is : 8
Solution Is : 50*8=400
Numerical Ability

One litre of water is evaporate from a 6 litre solution containing 4% sugar. The percentage of sugar in the remaining solution is ---

a) 24/5%
b) 4%
c) 3%
d) 10/3%


✔Answer
✔Solution
Correct Answer Is : 24/5%
Solution Is : Sugar solution = 6LITRES Concentration of sugar in 6 litres 4%=(6*4/100)=(24/100)=0.24 Since 1 litre of water has evaporated. Still the same amount of sugar will remain in the solution of 5 litres Concentration of 5 litre solution (new) is = (0.24/5) =(24/100*5)*100% =(24/5)%
Numerical Ability

When water is changed into ice, its volume increases by 9%. If ice changes into water, the percentage decrease in volume is ---

a) 9%
b) 10%
c) 18%
d) 900/109%


✔Answer
✔Solution
Correct Answer Is : 900/109%
Solution Is : Let the volume of the water be 100cc When the water changes into ice the volume increases by 9% the new volume =100+9% of 100 =109 cc Now if the ice, changes into water the volume decreases to 100cc.Let the % of decreases in volume be x 100cc=109cc-x% of 109 cc x % 109 cc = (109-100)cc =9cc x=(9/109)*100% =(900/109)%
Numerical Ability

A watch becomes fast by 5 minutes every day. By what percent does it become fast ?

a) 50/144%
b) 5%
c) 1/12%
d) 5/24%


✔Answer
✔Solution
Correct Answer Is : 50/144%
Solution Is : The watch becomes fast 5 mins everyday It`s % of 1 day =60*24=1440 minutes increase in speed everyday =(5/1440)*100 =(50/144)%
Numerical Ability

A bag contains 25 paise . 10 paise and 5 paise coins in the ration 1:2:3 . If their total value is ? 30, the number of 5 paise coins is ---

a) 50
b) 100
c) 150
d) 200


✔Answer
✔Solution
Correct Answer Is : 150
Solution Is : The ratio of 25p, 10p, 5p coins is 1:2:3 The number of 2p,10p,5p coins are x,2x and 3x respectively given 25*x+10*2x+5*3x=3000p 25x+20x+15x=3000 6x=3000 x=50p The number of 5p coins in 3x=3*50 =150p
Numerical Ability

The temperature of a place increases uniformly from 210° C to 380°C from 9 am to 2 pm. What was the temperature at noon?

a) 28.50°C
b) 270°C
c) 300°C
d) 320°C


✔Answer
✔Solution
Correct Answer Is : 320°C
Solution Is : Since the temperature increases uniformly The rise is temperature per hour from 9 am to 2 pm =(380°C-210°/5) =170°/5=34°C The temperature at noon =210°C+(3*34)°C =(210+102)°C =312°C =320°C
Numerical Ability

If 5 men or 9 women can do piece of work in 19days; 3 men and 6 women will do the same work in ----

a) 10days
b) 15days
c) 12days
d) 7days


✔Answer
✔Solution
Correct Answer Is : 15days
Solution Is :
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