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  • RRB NTPC Exam Arithmetic Ability Study Material

Digitization help student to explore and study their academic courses online, as this gives them flexibility and scheduling their learning at their convenience. Kidsfront has prepared unique course material of Arithmetic Ability Arithmetic for RRB NTPC Exam student. This free online Arithmetic Ability study material for RRB NTPC Exam will help students in learning and doing practice on Arithmetic topic of RRB NTPC Exam Arithmetic Ability . The study material on Arithmetic, help RRB NTPC Exam Arithmetic Ability students to learn every aspect of Arithmetic and prepare themselves for exams by doing online test exercise for Arithmetic, as their study progresses in class. Kidsfront provide unique pattern of learning Arithmetic Ability with free online comprehensive study material and loads of RRB NTPC Exam Arithmetic Ability Arithmetic exercise prepared by the highly professionals team. Students can understand Arithmetic concept easily and consolidate their learning by doing practice test on Arithmetic regularly till they excel in Arithmetic Ability Arithmetic.


Arithmetic
A tyre has two punctures. The first puncture alone would have made the tyre flat in 9 minutes and the second alone would have done it in 6 minutes. If the air leaks out at a constant rate, then how long does it take, in minutes, for both the punctures together to make it flat?

a) 1 1/2
b) 3 1/2
c) 3 3/5
d) 4 1/4


✔Answer
✔Solution
Correct Answer Is : 3 3/5
Solution Is : (A) In one minute, (1/9) + (1/6) = 15/24 = 5/18 of the tyre becomes flat. Therefore, the complete tyre will be flat in 18/5 = 3 3/5 minutes.
The fluid contained in a bucket can fill four " large " bottles or seven " small " bottles. A full large table is used to fill an empty small bottle. What fraction of the fluid is left over in the large bottle when the small one is full?

a) 2/7
b) 4/7
c) 3/7
d) 5/7


✔Answer
✔Solution
Correct Answer Is : 3/7
Solution Is : (B) 4 large bottles = 7 small bottles Therefore, 1 small bottle = 4/7 large bottle. => 3/7 of the fluid in large bottles is left after filling one small bottle from it.

Two trains start at the same time from A and B and proceed toward each other at the speed of 75 km/h and 50 km/h, respectively. When both meet at a point in between, one train found to be travelled 175 km more than the other. Find the distance between A and B.

a) 785
b) 875
c) 857
d) 758


✔Answer
✔Solution
Correct Answer Is : 875
Solution Is : According to the condition, = X/50=X+175/75
Where, x is the distance of the train which has speed is 50 km
75X=50X+50 x 175,25X =5870 ,x=350 ,Distance Between A and B is X +(X+175)=350+(350+175)=875

A candidate who gets 20% marks in an examination, fails by 30 marks. But if he gets 32 5 marks, he gets 42 marks more than the minimum pass marks. Find the pass percentage of marks:

a) 20%
b) 52%
c) 42%
d) 25%


✔Answer
✔Solution
Correct Answer Is : 25%
Solution Is : By condition 20% of x ? 30= 32% of x ? 42 - 20)%of x= 42 + 30 = 72
12% of x = 72
100% of x = 72 X 100 /12=600 ,Pass marks = 20% of 600 + 30 = (600 x 20)/100 + 30
= 120 +30= (150x100)/600
Per cent pass marks = 25%

Successive discounts of 20% and 10% are equivalent to single discount of

a) 0.28
b) 0.15
c) 0.3
d) 0.25


✔Answer
✔Solution
Correct Answer Is : 0.28
Solution Is : Equivalent to a single discount of successive discount = (A+B)-(AxB)/100=28%

Theaverage expenditure of a man for the first five months is Rs. 1200 and for the next seven months is Rs. 1300. If he saves Rs. 2900 in that year, his monthly average income is

a) Rs. 1700
b) Rs. 1600
c) Rs. 1400
d) Rs. 1500


✔Answer
✔Solution
Correct Answer Is : Rs. 1500
Solution Is : Average expenses of first 5 months = 1200
Average expenses of next 7 months = 1300
Saving of twetve months 2900
So, the total expenses of first 5 months = 6000
and total expenses of next 7 months = 9100
Sum of tweLve months= 15100
Saving of twelve months = 2900
Therefore, the total income of twelve months = 15100+ 2900
= 18000
Hence. the monthly income of a man = 12 = 1500

Thevulgar fraction of 0.3939 is

a) (13/33)
b) (17/39)
c) (11/39)
d) (15/33)


✔Answer
✔Solution
Correct Answer Is : (13/33)
Solution Is : (p/q)=(3939-39)/9900=39/99=13/33

merchant has 1000 kg sugar part of which he sells at 8°Io profit and the rest at 13% profit. He gains 14% on the whole. The quantity sold at 8°Io profit is

a) 400kg
b) 640kg
c) 600kg
d) 560kg


✔Answer
✔Solution
Correct Answer Is : 400kg
Solution Is : LetCP=C quantity of sugar on profit on 8%=x kg
1O8%of x X C + 118%of(1 000 -x) X C=114%of 1000 X C , 4000C=10 X C ,X=4000/10
Hence, required cuantity = 400kg

A man purchased an article for 1500 and sold it at 25% above the cost price. If he has to pay 75 as tax on it, his net profit percentage will be

a) 30
b) 25
c) 20
d) 15


✔Answer
✔Solution
Correct Answer Is : 20
Solution Is : The cost price of an article 1500
and the selling price of an articte= 125% of 1500= 1875
Amount of tax (pay)= 75
Then net prof (1875 ? 75 ? 1500) = 300
Per cent prof1= (300x100)/1500=20%

A number x is divisible by 7. When this number is divided by 8, 12 and 16, it leaves a remainder in each case. The least value of x is

a) 150
b) 149
c) 148
d) 147


✔Answer
✔Solution
Correct Answer Is : 147
Solution Is : LCM of 8. 12.16=48
Hence, the required number
= 48 x n + 3, dvisble by 7
= 48 x 3 + 3 = 147 divisible by 7 Let n =3

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