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  • SSC SI CAPF Exam Quantitative Aptitude Study Material

Digitization help student to explore and study their academic courses online, as this gives them flexibility and scheduling their learning at their convenience. Kidsfront has prepared unique course material of Quantitative Aptitude Problem on Ages for SSC SI CAPF Exam student. This free online Quantitative Aptitude study material for SSC SI CAPF Exam will help students in learning and doing practice on Problem on Ages topic of SSC SI CAPF Exam Quantitative Aptitude. The study material on Problem on Ages, help SSC SI CAPF Exam Quantitative Aptitude students to learn every aspect of Problem on Ages and prepare themselves for exams by doing online test exercise for Problem on Ages, as their study progresses in class. Kidsfront provide unique pattern of learning Quantitative Aptitude with free online comprehensive study material and loads of SSC SI CAPF Exam Quantitative Aptitude Problem on Ages exercise prepared by the highly professionals team. Students can understand Problem on Ages concept easily and consolidate their learning by doing practice test on Problem on Ages regularly till they excel in Quantitative Aptitude Problem on Ages.


Problem on Ages
The ratio of the ages of A and B at present is 3:1. Four years earlier the ratio was 4:1. The present age of A is

a) 48 years
b) 40 years
c) 36 years
d) 32 years


✔Answer
✔Solution
Correct Answer Is : 36 years
Solution Is : A`s present age = 3x years B`s present age = x years 4 years ago, 3x - 4 / x - 4 = 4/1 4x - 16 = 3x - 4 4x - 3x = 16 -4 x = 12 A`s present age 3x = 3 x 12 = 36 years
The present ages of three friends are in the proportions 6 : 7 : 8 . Five years ago, the sum of their ages was 48 years .Find out present ages in years?

a) 24,28,32
b) 18,21,24
c) 30,35,40
d) 12,14,16


✔Answer
✔Solution
Correct Answer Is : 18,21,24
Solution Is :
Three years ago, the average of a family of 5 members was 17 years. A baby having been born the average age of the family is the same day. The present age of the baby (in years) is

a) 2
b) 2.4
c) 3
d) 1.5


✔Answer
✔Solution
Correct Answer Is : 2
Solution Is : (1) Three years ago, Total age of the family = 17*5 =85 years Total age of five member family today = 85+15 = 100 years Total age of the family with child today= 17*6=102 years Age of baby = 102-100 =2 years
Shan is 55 years old, Sathian is 5 years junior to Shari and 6 years senior to Balan. The youngest brother of Balan is Devan and he is 7 years junior to him. So what is the age difference between Devan and Shah ?

a) 18 YRS
b) 15 yrs
c) 13 years
d) 7 years


✔Answer
✔Solution
Correct Answer Is : 18 YRS
Solution Is : Age of Sathian = 50 years
and age of Balan = 44 years
Age of Devan = 37 years
Reqd. difference = 55 - 37
= 18 years
I am three times as old as my son. 15 years hence, I will by twice as old as my son. The sum of our ages is

a) 48 years
b) 60 years
c) 64years
d) 72years


✔Answer
✔Solution
Correct Answer Is : 60 years
Solution Is : Let the son`s present age = x years.
Therefore Father`s present age = 3x years
After 15 years, 3x+ 15=2(x +15)
==>3x+ 15= 2x +30 ⇒x = 30 - 15 = 15
So Sum of their present ages =x+3x=4x
=4 × 15 = 60 years
At present, the ratio of the ages of Maya and Chhaya is 6:5 and fifteen years from now, the ratio will get changed to 9:8. Maya`s present age is

a) 21 years
b) 24 years
c) 30 years
d) 40 years


✔Answer
✔Solution
Correct Answer Is : 30 years
Solution Is : At present the ratio of ages of maya and chhaya is 6:5. After 15 years ,(6x+15)/(5x+15)= 9/8 ⇒48x+120 = 45x-135 ⇒3x=15. Therefore x=5. Hence the present age of maya is 6*5 =30
The average age of Ram and his two children is 17 years and the average age of Ram`s wife and the same children is 16 years. If the age of Ram is 33 years, the age of his wife is (in years):

a) 31
b) 32
c) 35
d) 30


✔Answer
✔Solution
Correct Answer Is : 30
Solution Is : Ram + two children =51 years
His wife + two children =48 years
Therefore, Ram -Wife =3 years
⇒ 33- wife =3 years
Therefore wife =33-3 = 30 years
Eighteen years ago, the ratio of A`s age to B`s age was 8 : 13. Their present ratios are 5 : 7. What is the present age of A ?

a) 70 years
b) 50 years
c) 40 years
d) 60 years


✔Answer
✔Solution
Correct Answer Is : 50 years
Solution Is : Let the A`s age and B`s age was 8x and 13x
According to question, (8x+18)/(13x+18) = 5/7
=> 56x+18*7 = 65x+18 *5
=> 65x-56x =18*7 - 18*5
=> 9x=18*2
x=4
Hence, the present age of A
=> 8*4+18 =50years.
The sum of the ages of two brothers, having a difference of 8 years between them, will double after 10 years. What is the ratio of the age of the younger brother to that of the elder brother ?

a) 10:13
b) 7 : 11
c) 3:07
d) 8:09


✔Answer
✔Solution
Correct Answer Is : 3:07
Solution Is : Age of younger brother =x years. Age of elder brother =(x+8) years.
Therefore after 10 years,
x+x+8+20=2(x+x+8)
2x+28=4x+16
4x-2x=28-16
2x=12 ⇒x=12/2 =6
Therefore required ratio
=6:(6+8) = 6:14 =3:7
X is four years older than Y who is twice as old as Z. If the total age of X, Y and Z be 34, how old is X?

a) 8
b) 10
c) 12
d) 16


✔Answer
✔Solution
Correct Answer Is : 16
Solution Is : Let Z`s age be x years. Then, Y`s age
= 2x years. X`s age = (2x + 4) y
ears. (2x + 4) + 2x + x = 34
5x = 30
x = 6
Hence, X`s age = 2x + 4 = 2 x 6 + 4 = 16 years.

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