The diagonal of a quadrilateral shaped field is 24m and the perpendiculars dropped on it from the remaining opposite vertices are 8 cm and 13 cm. The area of the field is

Correct Answer Is : 252 m²

Solution Is :

If the base right of right prism remains same and the lateral edges are halved, then its volume will be reduced by

Correct Answer Is : 50%

Solution Is : Volume of prism = Area of base x height Base remains constant. Hence, volume α height

The radius of a right circular cone is 3 cm and its height is 4 cm. The total surface area of the cone is

Correct Answer Is : 75.4 sq.cm

Solution Is :

A wooden box of dimensions 8 metre x 7 metre x6 metre is to carry rectangular boxes of dimensions 8 cm x 7 cm x6 cm. The maximum number of boxes that can be carried in 1 wooden box is

Correct Answer Is : 1000000

Solution Is : Volume of wooden box = (8 * 7 * 6) cu.m. = (8 * 7 * 6 * 100?3) cu.m. Maximum number of boxes = 8 * 7 * 6 * 100³/ 8 * 7 * 6 =1000000

Two circular cylinders of equal volume have their heights in the ratio 1 : 2. Ratio of their radii is

Correct Answer Is : √2 : 1

Solution Is :

A rectangular piece of paper of dimensions 22 cm by 12 cm is rolled along its length to form a cylinder. The Volume ( in cu. Cm) of the cylinder so formed is

Correct Answer Is : 462

Solution Is : Paper is folded along the length. Circumference of the base = 22 cm, Height of cylinder = 12 cm 2 π r = 22 => 2 * 22/7 * r = 22 => r = 7/2 cm Volume of cylinder = π r² h 22/7 * 7/2 * 7/2 * 12 = 462 cu.cm.

A sphere is placed inside a right circular cylinder so as to touch the top, base and the lateral surface of the cylinder. If the radius of the sphere is R, the volume of the cylinder is

a)
b)
c)
d)

Correct Answer Is :

Solution Is : Height of cylinder = 2 R units Radius of base = R units Volume of cylinder = π R² h => π(R²) (2R) = 2 π R?3

Correct Answer Is : 30°

Solution Is :

Correct Answer Is : None of these

Solution Is :