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  • SSC CGL Exam Quantitative Aptitude Study Material

Digitization help student to explore and study their academic courses online, as this gives them flexibility and scheduling their learning at their convenience. Kidsfront has prepared unique course material of Quantitative Aptitude Mensuration for SSC CGL Exam student. This free online Quantitative Aptitude study material for SSC CGL Exam will help students in learning and doing practice on Mensuration topic of SSC CGL Exam Quantitative Aptitude. The study material on Mensuration, help SSC CGL Exam Quantitative Aptitude students to learn every aspect of Mensuration and prepare themselves for exams by doing online test exercise for Mensuration, as their study progresses in class. Kidsfront provide unique pattern of learning Quantitative Aptitude with free online comprehensive study material and loads of SSC CGL Exam Quantitative Aptitude Mensuration exercise prepared by the highly professionals team. Students can understand Mensuration concept easily and consolidate their learning by doing practice test on Mensuration regularly till they excel in Quantitative Aptitude Mensuration.


Mensuration
A wooden box of dimensions 8 metre x 7 metre x6 metre is to carry rectangular boxes of dimensions 8 cm x 7 cm x6 cm. The maximum number of boxes that can be carried in 1 wooden box is

a) 7500000
b) 9800000
c) 1200000
d) 1000000



Answer
Solution
Correct Answer Is : 1000000
Solution Is : Volume of wooden box = (8 * 7 * 6) cu.m. = (8 * 7 * 6 * 100?3) cu.m. Maximum number of boxes = 8 * 7 * 6 * 1003/ 8 * 7 * 6 =1000000
Two circular cylinders of equal volume have their heights in the ratio 1 : 2. Ratio of their radii is

a) 1:04
b) 1 : √2
c) √2 : 1
d) 1:02



Answer
Solution
Correct Answer Is : √2 : 1
Solution Is :
A rectangular piece of paper of dimensions 22 cm by 12 cm is rolled along its length to form a cylinder. The Volume ( in cu. Cm) of the cylinder so formed is

a) 562
b) 412
c) 462
d) 362



Answer
Solution
Correct Answer Is : 462
Solution Is : Paper is folded along the length. Circumference of the base = 22 cm, Height of cylinder = 12 cm 2 π r = 22 => 2 * 22/7 * r = 22 => r = 7/2 cm Volume of cylinder = π r2 h 22/7 * 7/2 * 7/2 * 12 = 462 cu.cm.
A sphere is placed inside a right circular cylinder so as to touch the top, base and the lateral surface of the cylinder. If the radius of the sphere is R, the volume of the cylinder is

a)
b)
c)
d)



Answer
Solution
Correct Answer Is :
Solution Is : Height of cylinder = 2 R units Radius of base = R units Volume of cylinder = π R2 h => π(R2) (2R) = 2 π R?3

a) 60°
b) 20°
c) 30°
d) 50°



Answer
Solution
Correct Answer Is : 30°
Solution Is :

a) Equal to 3/4
b) Less than 3/4
c) Greater than 3/4
d) None of these



Answer
Solution
Correct Answer Is : None of these
Solution Is :
The total surface area of a regular triangular pyramid with each edge of length 1 cm is

a) 4√3 cm2
b) 4/3 √3 cm2
c) √3 cm2
d) 4 cm2



Answer
Solution
Correct Answer Is : √3 cm2
Solution Is : Total surface area = 4 x √3/4 x (1)2 = √3 sq.cm
The number of paving stones each measuring 2.5 m x 2m required to pave a rectangular courtyard 30m long and 17.5m wide is

a) 80
b) 33
c) 99
d) 105



Answer
Solution
Correct Answer Is : 105
Solution Is : Number of paving stones = Area of courtyard / Area of a stone = 30x 17.5 / 2.5 x 2 = 105
The perimeter of a sheet of paper in the shape of a quadrant of a circle is 75 cm. Its area would be ( π = 22/7)

a) 100 cm2
b) 346.5 cm2
c) 693 cm2
d) 512.25 cm2



Answer
Solution
Correct Answer Is : 346.5 cm2
Solution Is :
The perimeter of two similar triangles are 30 cm and 20 cm respectively. If one side of the first triangles is 9 cm. Determine the corresponding side of the second triangle.

a) 13.5 cm
b) 6 cm
c) 15 cm
d) 5cm



Answer
Solution
Correct Answer Is : 6 cm
Solution Is : If the required side be x cm, then 30/20 = 9/x => 3x = 9 x 2 => x = 9x2/3 = 6 cm
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