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  • SBI PO Exam Quantitative Aptitude Study Material

Digitization help student to explore and study their academic courses online, as this gives them flexibility and scheduling their learning at their convenience. Kidsfront has prepared unique course material of Quantitative Aptitude Speed, Time and Distance for SBI PO Exam student. This free online Quantitative Aptitude study material for SBI PO Exam will help students in learning and doing practice on Speed, Time and Distance topic of SBI PO Exam Quantitative Aptitude. The study material on Speed, Time and Distance, help SBI PO Exam Quantitative Aptitude students to learn every aspect of Speed, Time and Distance and prepare themselves for exams by doing online test exercise for Speed, Time and Distance, as their study progresses in class. Kidsfront provide unique pattern of learning Quantitative Aptitude with free online comprehensive study material and loads of SBI PO Exam Quantitative Aptitude Speed, Time and Distance exercise prepared by the highly professionals team. Students can understand Speed, Time and Distance concept easily and consolidate their learning by doing practice test on Speed, Time and Distance regularly till they excel in Quantitative Aptitude Speed, Time and Distance.


Speed, Time and Distance
A gun is fired at a distance of 1.34 km from Geeta. She hears the sound after 4 seconds. The speed at which sound travels is

a) 325 m/sec
b) 335 m/sec
c) 330 m/sec
d) 300 m/sec


✔Answer
✔Solution
Correct Answer Is : 335 m/sec
Solution Is : Speed of sound
=Distance/speed
=((1.34*1000)/4)metre/second
=(1340/4) metre/second
=335 metre/second
If I walk at 5Km/hr, I miss a train by 7 minutes. However, if I walk at 6 km/hr I reach the station 5 minutes before the departure of the train. The distance between my house and the station is

a) 5 km
b) 6.5 km
c) 7 km
d) 6 km


✔Answer
✔Solution
Correct Answer Is : 6 km
Solution Is : Distance of station from house
=xkm(let)
Difference of time
=7+5=12minutes =12/60 hour =1/5 hour
Time =distance/speed
Therefore (x/5)-(x/6)=1/5
⇒((6x-5x)/30)=1/5
⇒x/30=1/5
x=30/5 =6Km
A boat goes 24 km upstream and 28 km downstream in 6 hours. It goes 30 km upstream and 21 km downstream in 6 hours and 30 minutes. The speed of the boat in still water is

a) 8 km/hr
b) 9 km/hr
c) 12 km/hr
d) 10 km/hr


✔Answer
✔Solution
Correct Answer Is : 10 km/hr
Solution Is : 24/(x-y) + 28/(x+y) = 6
30/(x-y) + 21/(x+y) = 6.5
Taking 1/(x-y) as X and 1/(x+y) as Y
24X + 28Y = 6
30X + 21Y = 6.5
solving for X and Y=⇒
X = 1/6 and Y = 1/14
so x-y = 6 and x+y = 14 hence
x = 10 kmph and y = 4kmph
A and B are 20 km apart. A can walk at an average speed of 4 km/hour and B at 6 km/ hr. If they start walking towards each other at 7 a.m., when they will meet?

a) 8:00:00 AM
b) 8.30 AM
c) 9:00:00 AM
d) 10:00:00 AM


✔Answer
✔Solution
Correct Answer Is : 9:00:00 AM
Solution Is : 20 Km A<------------------------------------>B -->4kmph 6kmph<--
Relative speed = 4 + 6 =10 kmph
Time required to cover 20 km = 20/10 = 2 Hr
They started at 7 AM, so they will meet at 9 AM.
A policeman starts to chase a thief. When the thief goes 10 steps the policeman moves 8 steps. 5 steps of the policeman is equal to 7 steps of the thief. The ratio of the speeds of the policeman and the thief is

a) 25 : 28
b) 25 : 26
c) 28 : 25
d) 56 : 25



✔Answer
✔Solution
Correct Answer Is : 28 : 25
Solution Is : 5 steps of Policeman = 7 steps of thief
⇒ 1 step of Policeman = 7/5 steps of thief
⇒ 8 Steps of Policeman = 8 x 7/5 steps of thief = 56/5 steps of thief. ? Ratio of speeds of policeman and thief = ratio of distance covered by policeman and thief in same time
= In same time policeman moves 8 steps and thief moves 10 steps
= 56/5 : 10 (because as we calculated earlier 8 steps of policeman = 56/5 steps of thief )
= 56 : 50 = 28 : 25
An aeroplane covers a distance at a 340 kmph in 8 hours. To cover the same distance in 2 2/3 hour, it must travel at what speed?

a) 660 km/hr
b) 700 km/hr
c) 680 km/hr
d) 1020 km/hr


✔Answer
✔Solution
Correct Answer Is : 1020 km/hr
Solution Is : Distance = (340 x 8) = 2720 km.
Speed = Distance/Time
Given time is 2 2/3 hours = 2 + 2/3 = (2*3) + 2/3 = 8/3 hours
Therefore, speed = 2720/(8/3)
Required speed = 2720 * 3 / 8 = 340 * 3 = 1020 km/hr
Sarita and Julie start walking from the same place in the opposite direction. If Julie walks at a speed of 2½ km/hr and Sarita at a speed of 2 km/hr, in how much time will they be 18 km apart?

a) 4 hrs
b) 4.5 hrs
c) 5 hrs
d) 4.8 hrs


✔Answer
✔Solution
Correct Answer Is : 4 hrs
Solution Is : Distance = 125+115 = 240 m
Relative speed = 33+39 = 72 km/hr
= (72×10)/36 m/s
Time = distance/speed
= 240 / (72×10)/36
= 240×36 / 720
= 12 s
Two trains 125 meters and 115 meters in length, are running towards each other on parallel lines, one at the rate of 33 km/hr and the other at 39 km/hr. how much time (in seconds) will they take to pass each other from the moment they meet?

a) 8
b) 10
c) 12
d) 15


✔Answer
✔Solution
Correct Answer Is : 12
Solution Is : 650 = P(1+R/100)…. (i)
676 = P (1 + R/100)2….. (ii) ii is divided by I
(1 + R/100) = 26/25…… (iii)
Substituting iii in I, we get
650 = P x 26/25
26P = 16250
P = 625
A certain distance is coverec at a certain speed. If half of this distance is covered in double the time, the ratio of the two speeds is

a) 1:2
b) 4 : 1
c) 1 : 4
d) 2 : 1



✔Answer
✔Solution
Correct Answer Is : 4 : 1
Solution Is :
A man performs 2/15 of the total journey by train, 2/20 by bus and the remaining 10 km on foot. His total journey in km is

a) 15.6
b) 24
c) 16.4
d) 12.8


✔Answer
✔Solution
Correct Answer Is : 24
Solution Is : (2) If the total journey be of x km,then
2x/15+9x/20+10=x
⇒x-2x/15-9x/20=10
⇒25x/60=10
X=24 km
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