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  • SBI PO Exam Quantitative Aptitude Study Material

Digitization help student to explore and study their academic courses online, as this gives them flexibility and scheduling their learning at their convenience. Kidsfront has prepared unique course material of Quantitative Aptitude Pipes and Cisterns for SBI PO Exam student. This free online Quantitative Aptitude study material for SBI PO Exam will help students in learning and doing practice on Pipes and Cisterns topic of SBI PO Exam Quantitative Aptitude. The study material on Pipes and Cisterns, help SBI PO Exam Quantitative Aptitude students to learn every aspect of Pipes and Cisterns and prepare themselves for exams by doing online test exercise for Pipes and Cisterns, as their study progresses in class. Kidsfront provide unique pattern of learning Quantitative Aptitude with free online comprehensive study material and loads of SBI PO Exam Quantitative Aptitude Pipes and Cisterns exercise prepared by the highly professionals team. Students can understand Pipes and Cisterns concept easily and consolidate their learning by doing practice test on Pipes and Cisterns regularly till they excel in Quantitative Aptitude Pipes and Cisterns.


Pipes and Cisterns
A pipe can fill a cistern in 9 hours. Due to leak in its bottom, the cistern fills up in 10 hours. If cistern is full, in how much time will it be emptied by the leak?

a) 70 hours
b) 80 hours
c) 90 hours
d) 100 hours



Answer
Solution
Correct Answer Is : 90 hours
Solution Is : Part filled without leak in 1 hour = 1/9
Part filled with leak in 1 hour = 1/10
Work done by leak in 1 hour =1/9?1/10=1/90
We used subtraction as it is getting empty.
So total time to empty the cistern is 90 hours
Pipe A and B can fill a tank in 10 hours and 8 hours respectively. After certain time, pipe A was closed. It took a total of 6 hours to fill the tank completely. For how many hours did pipe A work?

a) 4 1/4 hours
b) 2 1/2 hours
c) 3 1/3 hours
d) 5 1/3 hours



Answer
Solution
Correct Answer Is : 2 1/2 hours
Solution Is : (2) Let pipe A remained open for x hours. According to the question, (x/10)+(6/8)=1 =>x/10=1-3/4=1/4 => x=10/4 = 2 1/2 hours
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