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  • SBI PO Exam Quantitative Aptitude Study Material

Digitization help student to explore and study their academic courses online, as this gives them flexibility and scheduling their learning at their convenience. Kidsfront has prepared unique course material of Quantitative Aptitude Area and Volume for SBI PO Exam student. This free online Quantitative Aptitude study material for SBI PO Exam will help students in learning and doing practice on Area and Volume topic of SBI PO Exam Quantitative Aptitude. The study material on Area and Volume, help SBI PO Exam Quantitative Aptitude students to learn every aspect of Area and Volume and prepare themselves for exams by doing online test exercise for Area and Volume, as their study progresses in class. Kidsfront provide unique pattern of learning Quantitative Aptitude with free online comprehensive study material and loads of SBI PO Exam Quantitative Aptitude Area and Volume exercise prepared by the highly professionals team. Students can understand Area and Volume concept easily and consolidate their learning by doing practice test on Area and Volume regularly till they excel in Quantitative Aptitude Area and Volume.


Area and Volume
If the volume of a sphere is numerically equal to its surface area then its diameter is:

a) 4cm
b) 2cm
c) 3cm
d) 6cm


✔Answer
✔Solution
Correct Answer Is : 6cm
Solution Is : According to question
Volume of sphere= surfae area of sphere
(4/3)πr3 = 4πr2
⇒ r = 3cm diameter = 6 cm
5 person will live in a tent. If each person requires 16m2 of floor area and 100m3 space for air then the height of the cone of smallest size to accommodate these persons would be?

a) 18.75m
b) 16m
c) 10.25m
d) 20m


✔Answer
✔Solution
Correct Answer Is : 18.75m
Solution Is :
If the altitude of an equilateral triangle is 12√3cm, then its area would be:

a) 12cm2
b) 72cm2
c) 36√3cm2
d) 144√3cm2


✔Answer
✔Solution
Correct Answer Is : 144√3cm2
Solution Is :
Let ABC is equilateral triangle.
Where sides is a cm.
⇒ Area of equilateral triangle =(?3/4)a2)
⇒ (1/2)*9*AD = (?3/4)a2
⇒ (1/2)*12?3 =(?3/4)a
⇒ a=24cm.
Now, Area of triangle =((?3/4)a2)
=(?3/4)*24*24 = 148?3cm
The area of the triangle formed by the graphs of the equations x=0, 2x+3y=6 and x+y=3 is:

a) 3sq.unit
b) 1 1/2sq.unit
c) 1sq.unit
d) 4 1/2sq.unit


✔Answer
✔Solution
Correct Answer Is : 1 1/2sq.unit
Solution Is : X=0. 2X+3Y=6. 2X+Y=3.
2x + 3y = 6 ...(ii)
x = 0, y = 2
x = 3, y = 0
From eqn.
(iii) x+ y = 3
x = 0, y = 3
x = 3, y = 0
Area made by these three lines
= Area of triangle OBC – Area of OAC
=(1/2)*3*3-(1/2)*2*3 =(9/2)-3 =3/2 = 1 1/2 sq.
If D, E and F are the mid points of BC, CA and AB respectively of the AABC then the ratio of area of the parallelogram DEFB and area of the trapezium CAFD is :

a) 1:3
b) 1:2
c) 3:4
d) 2:3


✔Answer
✔Solution
Correct Answer Is : 2:3
Solution Is :
Average weight of 3 men, A, B, C is 84 kg. Another man D joins the group and the average now becomes 80 kg. If another man E whose weight is 3 kg more than that of D replaces A then the average weight of B, C, D and E becomes 79 kg. The weight of A in kg. is

a) 80
b) 70
c) 72
d) 75


✔Answer
✔Solution
Correct Answer Is : 75
Solution Is : (4) Let A,B,C,Dand E are in kg.represent their weights.Then Therefore,A+B+C=84*3=252 kg A+B+C+D=80*4=320 kg Therefore,D=(320-252)kg=68 kg E=68+3=71kg. B+C+D+E=79*4=316kg. Now, (A+B+C+D)-(B+C+D+E)=320-316 A-E=4kg. Therefore, A=4+E=4+71=75kg.
The area of the triangle formed by the graphs of the equations x = 4, y = 3 and 3x+ 4y = 12 is

a) 4 sq. unit
b) 3 sq. unit
c) 6 sq. unit
d) 12 sq. unit


✔Answer
✔Solution
Correct Answer Is : 6 sq. unit
Solution Is : X=4
❑(⇒┴ equation of a line parallel to y-axis. y=3)
❑(⇒┴ equation of a line parallel to x-axis)
Putting x=0 in the equation
3x+4y=12,
3×0+4y=12 ❑(⇒┴ y=12/4=3)
?co-ordinates of the point of
intersection on y-axis=(0,3)
Again putting y=0 in the
equation 3x+4y=12,
3x+4×0=12 ❑(⇒┴ )x=12/3=4
?co-ordinates of the point of
intersection on x-axis=(4,0) AC = 3units,BC= 4 units Therefore Area of ΔABC =1/2 ×BC×AC =1/2 ×4×3 = 6 sq.units
If the area of the base, height and volume of a right prism be ((3√3)/2) P2 cm2,100√3 cm and 7200 cm’ ‘respectively, then the value of P will be

a) √3
b) 3/2
c) 2/√3
d) 4


✔Answer
✔Solution
Correct Answer Is : 4
Solution Is :
AB and CD are two parallel chords of a circle lying on the opposite side of the centre and the distance between them is 17 cm. The length of AB and CD are 10 cm and 24 cm respectively. The radius (in cm) of the circle is :

a) 13
b) 9
c) 18
d) 15


✔Answer
✔Solution
Correct Answer Is : 13
Solution Is :
AC is transverse common tangent to two circles with centres P and Q and radii 6 cm and 3 cm at the point A and C respectively. If AC cuts PQ at the point B and AB = 8cm then the length of PQ is :

a) 13 cm
b) 12 cm
c) 10 cm
d) 15, cm


✔Answer
✔Solution
Correct Answer Is : 15, cm
Solution Is :
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