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  • IBPS PO CWE Exam Quantitative Aptitude Study Material

Digitization help student to explore and study their academic courses online, as this gives them flexibility and scheduling their learning at their convenience. Kidsfront has prepared unique course material of Quantitative Aptitude Problems on Age for IBPS PO CWE Exam student. This free online Quantitative Aptitude study material for IBPS PO CWE Exam will help students in learning and doing practice on Problems on Age topic of IBPS PO CWE Exam Quantitative Aptitude. The study material on Problems on Age, help IBPS PO CWE Exam Quantitative Aptitude students to learn every aspect of Problems on Age and prepare themselves for exams by doing online test exercise for Problems on Age, as their study progresses in class. Kidsfront provide unique pattern of learning Quantitative Aptitude with free online comprehensive study material and loads of IBPS PO CWE Exam Quantitative Aptitude Problems on Age exercise prepared by the highly professionals team. Students can understand Problems on Age concept easily and consolidate their learning by doing practice test on Problems on Age regularly till they excel in Quantitative Aptitude Problems on Age.


Problems on Age
I am three times as old as my son. 15 years hence, I will by twice as old as my son. The sum of our ages is

a) 48 years
b) 60 years
c) 64years
d) 72years


✔Answer
✔Solution
Correct Answer Is : 60 years
Solution Is : Let the son`s present age = x years.
Therefore Father`s present age = 3x years
After 15 years, 3x+ 15=2(x +15)
==>3x+ 15= 2x +30 ⇒x = 30 - 15 = 15
So Sum of their present ages =x+3x=4x
=4 × 15 = 60 years
At present, the ratio of the ages of Maya and Chhaya is 6:5 and fifteen years from now, the ratio will get changed to 9:8. Maya`s present age is

a) 21 years
b) 24 years
c) 30 years
d) 40 years


✔Answer
✔Solution
Correct Answer Is : 30 years
Solution Is : At present the ratio of ages of maya and chhaya is 6:5. After 15 years ,(6x+15)/(5x+15)= 9/8 ⇒48x+120 = 45x-135 ⇒3x=15. Therefore x=5. Hence the present age of maya is 6*5 =30
The average age of Ram and his two children is 17 years and the average age of Ram`s wife and the same children is 16 years. If the age of Ram is 33 years, the age of his wife is (in years):

a) 31
b) 32
c) 35
d) 30


✔Answer
✔Solution
Correct Answer Is : 30
Solution Is : Ram + two children =51 years
His wife + two children =48 years
Therefore, Ram -Wife =3 years
⇒ 33- wife =3 years
Therefore wife =33-3 = 30 years
Eighteen years ago, the ratio of A`s age to B`s age was 8 : 13. Their present ratios are 5 : 7. What is the present age of A ?

a) 70 years
b) 50 years
c) 40 years
d) 60 years


✔Answer
✔Solution
Correct Answer Is : 50 years
Solution Is : Let the A`s age and B`s age was 8x and 13x
According to question, (8x+18)/(13x+18) = 5/7
=> 56x+18*7 = 65x+18 *5
=> 65x-56x =18*7 - 18*5
=> 9x=18*2
x=4
Hence, the present age of A
=> 8*4+18 =50years.
The sum of the ages of two brothers, having a difference of 8 years between them, will double after 10 years. What is the ratio of the age of the younger brother to that of the elder brother ?

a) 10:13
b) 7 : 11
c) 3:07
d) 8:09


✔Answer
✔Solution
Correct Answer Is : 3:07
Solution Is : Age of younger brother =x years. Age of elder brother =(x+8) years.
Therefore after 10 years,
x+x+8+20=2(x+x+8)
2x+28=4x+16
4x-2x=28-16
2x=12 ⇒x=12/2 =6
Therefore required ratio
=6:(6+8) = 6:14 =3:7
X is four years older than Y who is twice as old as Z. If the total age of X, Y and Z be 34, how old is X?

a) 8
b) 10
c) 12
d) 16


✔Answer
✔Solution
Correct Answer Is : 16
Solution Is : Let Z`s age be x years. Then, Y`s age
= 2x years. X`s age = (2x + 4) y
ears. (2x + 4) + 2x + x = 34
5x = 30
x = 6
Hence, X`s age = 2x + 4 = 2 x 6 + 4 = 16 years.
A man had 7 children. When their average age was 12 years, a child aged 6 died. The average age of remaing 6 children is

a) 13 years
b) 10 years
c) 11 years
d) 14 years


✔Answer
✔Solution
Correct Answer Is : 13 years
Solution Is : Average age of 7 children = 12 years.
Therefore, Excess of average age than the age of child died
= 12 - 6. = 6 years.
Therefore, Increase in ages of the remaining 6 children = 6/6 = 1 years
Therefore, ages of remaining 6 children = 12 + 1 = 13 years.
The average age of three boys is 15 yr. If their ages are in the ratio of 3 : 5 : 7, then the age of the youngest boy (in yr) is

a) 18
b) 21
c) 9
d) 15


✔Answer
✔Solution
Correct Answer Is : 9
Solution Is :
The average age of father and his son is 22 years. The ratio of their ages is 10 : 1 respectively. What is the age of the son ?

a) 24
b) 4
c) 40
d) 14


✔Answer
✔Solution
Correct Answer Is : 4
Solution Is : (2) Suppose the age of son is x years
Therefore, age of father=10x years
According to the question,
(10x+x)/2=22
⇒11x=44
∴x=44/11=4 years
Age of father = 10×4=40 years.
Veni is an year older than Smith. Smith is two years older than Salim. Raju is an year older than Salim. Who is the youngest of all ?

a) Raju
b) Salim
c) Veni
d) Smith


✔Answer
✔Solution
Correct Answer Is : Salim
Solution Is : (2). Suppose the age of salim is x years
Age of Raju = x+1 year
Age of Raju = x+2 year
Age of Raju = x+3 year,
Therefore, the salim is young for all.
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