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  • IBPS PO CWE Exam Quantitative Aptitude Study Material

Digitization help student to explore and study their academic courses online, as this gives them flexibility and scheduling their learning at their convenience. Kidsfront has prepared unique course material of Quantitative Aptitude Problems on Age for IBPS PO CWE Exam student. This free online Quantitative Aptitude study material for IBPS PO CWE Exam will help students in learning and doing practice on Problems on Age topic of IBPS PO CWE Exam Quantitative Aptitude. The study material on Problems on Age, help IBPS PO CWE Exam Quantitative Aptitude students to learn every aspect of Problems on Age and prepare themselves for exams by doing online test exercise for Problems on Age, as their study progresses in class. Kidsfront provide unique pattern of learning Quantitative Aptitude with free online comprehensive study material and loads of IBPS PO CWE Exam Quantitative Aptitude Problems on Age exercise prepared by the highly professionals team. Students can understand Problems on Age concept easily and consolidate their learning by doing practice test on Problems on Age regularly till they excel in Quantitative Aptitude Problems on Age.


Problems on Age
The sum of the ages of two brothers, having a difference of 8 years between them, will double after 10 years. What is the ratio of the age of the younger brother to that of the elder brother ?

a) 10:13
b) 7 : 11
c) 3:07
d) 8:09


✔Answer
✔Solution
Correct Answer Is : 3:07
Solution Is : Age of younger brother =x years. Age of elder brother =(x+8) years.
Therefore after 10 years,
x+x+8+20=2(x+x+8)
2x+28=4x+16
4x-2x=28-16
2x=12 ⇒x=12/2 =6
Therefore required ratio
=6:(6+8) = 6:14 =3:7
X is four years older than Y who is twice as old as Z. If the total age of X, Y and Z be 34, how old is X?

a) 8
b) 10
c) 12
d) 16


✔Answer
✔Solution
Correct Answer Is : 16
Solution Is : Let Z`s age be x years. Then, Y`s age
= 2x years. X`s age = (2x + 4) y
ears. (2x + 4) + 2x + x = 34
5x = 30
x = 6
Hence, X`s age = 2x + 4 = 2 x 6 + 4 = 16 years.
A man had 7 children. When their average age was 12 years, a child aged 6 died. The average age of remaing 6 children is

a) 13 years
b) 10 years
c) 11 years
d) 14 years


✔Answer
✔Solution
Correct Answer Is : 13 years
Solution Is : Average age of 7 children = 12 years.
Therefore, Excess of average age than the age of child died
= 12 - 6. = 6 years.
Therefore, Increase in ages of the remaining 6 children = 6/6 = 1 years
Therefore, ages of remaining 6 children = 12 + 1 = 13 years.
The average age of three boys is 15 yr. If their ages are in the ratio of 3 : 5 : 7, then the age of the youngest boy (in yr) is

a) 18
b) 21
c) 9
d) 15


✔Answer
✔Solution
Correct Answer Is : 9
Solution Is :
The average age of father and his son is 22 years. The ratio of their ages is 10 : 1 respectively. What is the age of the son ?

a) 24
b) 4
c) 40
d) 14


✔Answer
✔Solution
Correct Answer Is : 4
Solution Is : (2) Suppose the age of son is x years
Therefore, age of father=10x years
According to the question,
(10x+x)/2=22
⇒11x=44
∴x=44/11=4 years
Age of father = 10×4=40 years.
Veni is an year older than Smith. Smith is two years older than Salim. Raju is an year older than Salim. Who is the youngest of all ?

a) Raju
b) Salim
c) Veni
d) Smith


✔Answer
✔Solution
Correct Answer Is : Salim
Solution Is : (2). Suppose the age of salim is x years
Age of Raju = x+1 year
Age of Raju = x+2 year
Age of Raju = x+3 year,
Therefore, the salim is young for all.
The ratio of the ages of A and B at present is 3:1. Four years earlier the ratio was 4:1. The present age of A is

a) 48 years
b) 40 years
c) 36 years
d) 32 years


✔Answer
✔Solution
Correct Answer Is : 36 years
Solution Is : A`s present age = 3x years B`s present age = x years 4 years ago, 3x - 4 / x - 4 = 4/1 4x - 16 = 3x - 4 4x - 3x = 16 -4 x = 12 A`s present age 3x = 3 x 12 = 36 years
The present ages of three friends are in the proportions 6 : 7 : 8 . Five years ago, the sum of their ages was 48 years .Find out present ages in years?

a) 24,28,32
b) 18,21,24
c) 30,35,40
d) 12,14,16


✔Answer
✔Solution
Correct Answer Is : 18,21,24
Solution Is :
Three years ago, the average of a family of 5 members was 17 years. A baby having been born the average age of the family is the same day. The present age of the baby (in years) is

a) 2
b) 2.4
c) 3
d) 1.5


✔Answer
✔Solution
Correct Answer Is : 2
Solution Is : (1) Three years ago, Total age of the family = 17*5 =85 years Total age of five member family today = 85+15 = 100 years Total age of the family with child today= 17*6=102 years Age of baby = 102-100 =2 years
Shan is 55 years old, Sathian is 5 years junior to Shari and 6 years senior to Balan. The youngest brother of Balan is Devan and he is 7 years junior to him. So what is the age difference between Devan and Shah ?

a) 18 YRS
b) 15 yrs
c) 13 years
d) 7 years


✔Answer
✔Solution
Correct Answer Is : 18 YRS
Solution Is : Age of Sathian = 50 years
and age of Balan = 44 years
Age of Devan = 37 years
Reqd. difference = 55 - 37
= 18 years
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