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  • UIIC ASSISTANT RECRUITMENT Numerical Ability Study Material

Digitization help student to explore and study their academic courses online, as this gives them flexibility and scheduling their learning at their convenience. Kidsfront has prepared unique course material of Numerical Ability Simplification for UIIC ASSISTANT RECRUITMENT student. This free online Numerical Ability study material for UIIC ASSISTANT RECRUITMENT will help students in learning and doing practice on Simplification topic of UIIC ASSISTANT RECRUITMENT Numerical Ability. The study material on Simplification, help UIIC ASSISTANT RECRUITMENT Numerical Ability students to learn every aspect of Simplification and prepare themselves for exams by doing online test exercise for Simplification, as their study progresses in class. Kidsfront provide unique pattern of learning Numerical Ability with free online comprehensive study material and loads of UIIC ASSISTANT RECRUITMENT Numerical Ability Simplification exercise prepared by the highly professionals team. Students can understand Simplification concept easily and consolidate their learning by doing practice test on Simplification regularly till they excel in Numerical Ability Simplification.


Simplification
Simplify: √-50 + √-18 ? √-8

a) 8√2
b) 7√2
c) 6√2
d) 5√2


✔Answer
✔Solution
Correct Answer Is : 6√2
Solution Is : Given , √-50 + √-18 ? √-8 √25 x √-2 + √9 x √-2 - √4 x √-2 = 5x√-2 + 3x√-2 - 2 x √-2 = 6 √-2
Simplify (81 x2 - 49 y2 ) / ( 9x + 7y)

a) 9x + 7y
b) 9x - 7y
c) 9x
d) 7y


✔Answer
✔Solution
Correct Answer Is : 9x - 7y
Solution Is : Given 81 x2 - 49 y2 / 9x + 7y = 92 72 y2 / 9x + 7y = ( 9x + 7y ) ( 9x - 7y ) / 9x + 7y = 9x - 7y
5. Find the value of
( ( 0.0112 - 0.0012 ) 0f 0.14 + 0.25 x 0.2 ) / ( 0.02 x 0.01)

a) 257
b) 25.7
c) 2.57
d) 0.0257


✔Answer
✔Solution
Correct Answer Is : 257
Solution Is : ( (0.0112 - 0.0012) 0f 0.14 + 0.25 x 0.2 ) / (0.02 x 0.01) ( 0.01 x 0.14 + 0.25x 0.2 ) / 0.0002 = ( 0.0014 + 0.05) / 0.0002 = 0.0514 / 0.0002 = 514 / 2 = 257
Simplify:
( 2 1/3 - 1 1/2 ) of 3/5 + 1 2/5 / 2 1/3

a) 1 / 10
b) 3 / 10
c) 1 1/10
d) 1


✔Answer
✔Solution
Correct Answer Is : 1 1/10
Solution Is : ( 2 1/3 - 1 1/2 ) of 3/5 + 1 2/5 / 2 1/3 = ( 7/3 - 3/2 ) * 3/5 + 7/5 / 7/3 = 14-9 /6 * 3/5 + 7/5 * 3/7 = 5/6 * 3/5 + 3/5 = 1/2 + 3/5 = 5 + 6 / 10 = 11 / 10 = 1 1/10
If ! = / , # = +, ^ =

a) 68
b) 61
c) 54
d) 65


✔Answer
✔Solution
Correct Answer Is : 61
Solution Is : Calculate the value of 32 ! 4 ^ 7 # 5 Given , ! = / , # = +, ^ = ? , 32 / 4 x 7 + 5 = 8 x 7 + 5 = 56 + 5 = 61
The correct Value of(0.01)+(0.01)2 is

a) 0.0101
b) 0.1001
c) 0.0011
d) 0.0001


✔Answer
✔Solution
Correct Answer Is : 0.0101
Solution Is : (0.01)+(0.01)2=0.01+0.0001=0.0101
Following the equations are solved on the basis of a certain system. On the same basis find out the correct answer for the un solved equation.
8+5+3=358, 3+7+6=673, 4+7+6=?

a) 476
b) 674
c) 764
d) 746


✔Answer
✔Solution
Correct Answer Is : 476
Solution Is :


a) 1.04
b) 0.96
c) 0.92
d) 0.84


✔Answer
✔Solution
Correct Answer Is : 0.96
Solution Is :
√(√0.000064) is equal to

a) 0.0002
b) 0.002
c) 0.02
d) 0.2


✔Answer
✔Solution
Correct Answer Is : 0.2
Solution Is :


a)
b)
c)
d)



✔Answer
✔Solution
Correct Answer Is :
Solution Is :

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