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SBI SO Exam Quantitative Aptitude Study Material

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Mensuration

The total surface area of a regular triangular pyramid with each edge of length 1 cm is

a) 4√3 cm²
b) 4/3 √3 cm²
c) √3 cm²
d) 4 cm²

✔Answer

✔Solution

Correct Answer Is : √3 cm²

Solution Is : Total surface area = 4 x √3/4 x (1)² = √3 sq.cm

The number of paving stones each measuring 2.5 m x 2m required to pave a rectangular courtyard 30m long and 17.5m wide is

a) 80
b) 33
c) 99
d) 105

✔Answer

✔Solution

Correct Answer Is : 105

Solution Is : Number of paving stones = Area of courtyard / Area of a stone = 30x 17.5 / 2.5 x 2 = 105

The perimeter of a sheet of paper in the shape of a quadrant of a circle is 75 cm. Its area would be ( π = 22/7)

a) 100 cm²
b) 346.5 cm²
c) 693 cm²
d) 512.25 cm²

✔Answer

✔Solution

Correct Answer Is : 346.5 cm²

Solution Is :

The perimeter of two similar triangles are 30 cm and 20 cm respectively. If one side of the first triangles is 9 cm. Determine the corresponding side of the second triangle.

a) 13.5 cm
b) 6 cm
c) 15 cm
d) 5cm

✔Answer

✔Solution

Correct Answer Is : 6 cm

Solution Is : If the required side be x cm, then 30/20 = 9/x => 3x = 9 x 2 => x = 9x2/3 = 6 cm

The diagonal of a quadrilateral shaped field is 24m and the perpendiculars dropped on it from the remaining opposite vertices are 8 cm and 13 cm. The area of the field is

a) 252 m²
b) 156 m²
c) 96 m²
d) 1152 m²

✔Answer

✔Solution

Correct Answer Is : 252 m²

Solution Is :

If the base right of right prism remains same and the lateral edges are halved, then its volume will be reduced by

a) 33.33%
b) 66%
c) 25%
d) 50%

✔Answer

✔Solution

Correct Answer Is : 50%

Solution Is : Volume of prism = Area of base x height Base remains constant. Hence, volume α height

The radius of a right circular cone is 3 cm and its height is 4 cm. The total surface area of the cone is

a) 48.4 sq.cm
b) 64.4 sq.cm
c) 96.4 sq.cm
d) 75.4 sq.cm

✔Answer

✔Solution

Correct Answer Is : 75.4 sq.cm

Solution Is :

A wooden box of dimensions 8 metre x 7 metre x6 metre is to carry rectangular boxes of dimensions 8 cm x 7 cm x6 cm. The maximum number of boxes that can be carried in 1 wooden box is

a) 7500000
b) 9800000
c) 1200000
d) 1000000

✔Answer

✔Solution

Correct Answer Is : 1000000

Solution Is : Volume of wooden box = (8 * 7 * 6) cu.m. = (8 * 7 * 6 * 100?3) cu.m. Maximum number of boxes = 8 * 7 * 6 * 100³/ 8 * 7 * 6 =1000000

Two circular cylinders of equal volume have their heights in the ratio 1 : 2. Ratio of their radii is

a) 1:04
b) 1 : √2
c) √2 : 1
d) 1:02

✔Answer

✔Solution

Correct Answer Is : √2 : 1

Solution Is :

A rectangular piece of paper of dimensions 22 cm by 12 cm is rolled along its length to form a cylinder. The Volume ( in cu. Cm) of the cylinder so formed is

a) 562
b) 412
c) 462
d) 362

✔Answer

✔Solution

Correct Answer Is : 462

Solution Is : Paper is folded along the length. Circumference of the base = 22 cm, Height of cylinder = 12 cm 2 π r = 22 => 2 * 22/7 * r = 22 => r = 7/2 cm Volume of cylinder = π r² h 22/7 * 7/2 * 7/2 * 12 = 462 cu.cm.

SBI SO Exam Quantitative Aptitude Study Material

Mensuration

The total surface area of a regular triangular pyramid with each edge of length 1 cm is

Correct Answer Is : √3 cm2

Solution Is : Total surface area = 4 x √3/4 x (1)2 = √3 sq.cm

The number of paving stones each measuring 2.5 m x 2m required to pave a rectangular courtyard 30m long and 17.5m wide is

Correct Answer Is : 105

Solution Is : Number of paving stones = Area of courtyard / Area of a stone = 30x 17.5 / 2.5 x 2 = 105

The perimeter of a sheet of paper in the shape of a quadrant of a circle is 75 cm. Its area would be ( π = 22/7)

Correct Answer Is : 346.5 cm2

Solution Is :

The perimeter of two similar triangles are 30 cm and 20 cm respectively. If one side of the first triangles is 9 cm. Determine the corresponding side of the second triangle.

Correct Answer Is : 6 cm

Solution Is : If the required side be x cm, then 30/20 = 9/x => 3x = 9 x 2 => x = 9x2/3 = 6 cm

The diagonal of a quadrilateral shaped field is 24m and the perpendiculars dropped on it from the remaining opposite vertices are 8 cm and 13 cm. The area of the field is

Correct Answer Is : 252 m2

Solution Is :

If the base right of right prism remains same and the lateral edges are halved, then its volume will be reduced by

Correct Answer Is : 50%

Solution Is : Volume of prism = Area of base x height Base remains constant. Hence, volume α height

The radius of a right circular cone is 3 cm and its height is 4 cm. The total surface area of the cone is

Correct Answer Is : 75.4 sq.cm

Solution Is :

A wooden box of dimensions 8 metre x 7 metre x6 metre is to carry rectangular boxes of dimensions 8 cm x 7 cm x6 cm. The maximum number of boxes that can be carried in 1 wooden box is

Correct Answer Is : 1000000

Solution Is : Volume of wooden box = (8 * 7 * 6) cu.m. = (8 * 7 * 6 * 100?3) cu.m. Maximum number of boxes = 8 * 7 * 6 * 1003/ 8 * 7 * 6 =1000000

Two circular cylinders of equal volume have their heights in the ratio 1 : 2. Ratio of their radii is

Correct Answer Is : √2 : 1

Solution Is :

A rectangular piece of paper of dimensions 22 cm by 12 cm is rolled along its length to form a cylinder. The Volume ( in cu. Cm) of the cylinder so formed is

Correct Answer Is : 462

Solution Is : Paper is folded along the length. Circumference of the base = 22 cm, Height of cylinder = 12 cm 2 π r = 22 => 2 * 22/7 * r = 22 => r = 7/2 cm Volume of cylinder = π r2 h 22/7 * 7/2 * 7/2 * 12 = 462 cu.cm.

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Correct Answer Is : √3 cm²

Solution Is : Total surface area = 4 x √3/4 x (1)² = √3 sq.cm

Correct Answer Is : 346.5 cm²

Correct Answer Is : 252 m²

Solution Is : Volume of wooden box = (8 * 7 * 6) cu.m. = (8 * 7 * 6 * 100?3) cu.m. Maximum number of boxes = 8 * 7 * 6 * 100³/ 8 * 7 * 6 =1000000

Solution Is : Paper is folded along the length. Circumference of the base = 22 cm, Height of cylinder = 12 cm 2 π r = 22 => 2 * 22/7 * r = 22 => r = 7/2 cm Volume of cylinder = π r² h 22/7 * 7/2 * 7/2 * 12 = 462 cu.cm.