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UIIC ASSISTANT RECRUITMENT Reasoning Study Material

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Arithmetic reasoning

Thesum of ages of mother, daughter and son is 87 yr. What will be the sum of their ages after 8 yr?

a) 105
b) 101
c) 110
d) 111

✔Answer

✔Solution

Correct Answer Is : 111

Solution Is : The required total = 87 + 8 x 3 87 + 24 = 111 yr

>Choose the similar group of numbers on the basis of certain common properties they Possess.
(72, 66, 96)

a) (63, 70, 86)
b) (54. 57, 78)
c) (24, 69. 58)
d) (55, 66. 77)

✔Answer

✔Solution

Correct Answer Is : (55, 66. 77)

Solution Is : As. in (72, 66. 96). each number is divisible tx/ 6.
Similarly, in (55 66, 77), each number is divisible by 11

Ali had € 320. He spent

a) 120
b) €90
c) €70
d) €100

✔Answer

✔Solution

Correct Answer Is : €70

Solution Is : After purchasing the watch, the remaining amount of Ali
= 320 - 320 x 3/4 = 320 80 x 3 = € (320 -240) = €80
After purchasing the pen, remaining amount of Ali
= 80 - 80 x 1/8 = 80 - 10 = €70

Let a # b # c # d=ab-cd. If x= 6 # 3 # 5 # 4, What is the value of 7 # x # 3 # 11 ?

a) 19
b) 37
c) -47
d) -19

✔Answer

✔Solution

Correct Answer Is : -47

Solution Is :

Q.In a class, there are 80 students who study both Computer Science and Electronics. While 100 students study Computer Science, 120 students study Electronics. How many of them study Computer Science only ?

a) 100
b) 40
c) 180
d) 20

✔Answer

✔Solution

Correct Answer Is : 20

Solution Is :

Q.In an examination, Rahul got the 11th rank and he was 47th from the bottom among those who passed 3 students could not appear from the exam. 1 student failed. What is the total number of students ?

a) 60
b) 62
c) 59
d) 61

✔Answer

✔Solution

Correct Answer Is : 61

Solution Is : Number of successful candidates = 11 + 47 - 1 = 57 Total number of students = 57 + 3 + 1 = 61.

Arrange the given dates of birth in descending chronology.
1. 15.04.1950
2. 14.05.1960
3. 14.06.1960
4. 20.04.1950
5. 25.05.1960

a) 1, 5, 2, 3, 4
b) 1, 3, 2, 4, 5
c) 1, 4, 2, 5, 3
d) 1, 2, 4, 5, 3

✔Answer

✔Solution

Correct Answer Is : 1, 4, 2, 5, 3

Solution Is :

Thetotal number of students in class A and class B is 120 . If 15 students from class A are taken and added to class B, the number in Class B becomes twice that of A. Find out the number of students in Class A in the beginning .

a) 80
b) 65
c) 55
d) 40

✔Answer

✔Solution

Correct Answer Is : 55

Solution Is : Suppose total number of students in class
A = x
Total number of students in class B = 120 -x
Then , (120-x +15 ) = 2 ( x - 15 )
135 - x = 2x - 30
3x = 165
x = 165 / 3
x = 55

Inf 5=5,6=12,7=21,8=32 ,then 9 is equal to

a) 9
b) 27
c) 36
d) 45

✔Answer

✔Solution

Correct Answer Is : 45

Solution Is : 51 = 5
62=12
73=21
84=32
9*5=45

Which among the following is a leap year?

a) 1600
b) 1900
c) 1800
d) All of these

✔Answer

✔Solution

Correct Answer Is : 1600

Solution Is : Centuries should be divided by 400 hence only 1600 is divided by 400 , hence 1600 is a leap year

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UIIC ASSISTANT RECRUITMENT Reasoning Study Material

Arithmetic reasoning

Thesum of ages of mother, daughter and son is 87 yr. What will be the sum of their ages after 8 yr?

Correct Answer Is : 111

Solution Is : The required total = 87 + 8 x 3 87 + 24 = 111 yr

>Choose the similar group of numbers on the basis of certain common properties they Possess. (72, 66, 96)

Correct Answer Is : (55, 66. 77)

Solution Is : As. in (72, 66. 96). each number is divisible tx/ 6. Similarly, in (55 66, 77), each number is divisible by 11

Ali had € 320. He spent

Correct Answer Is : €70

Solution Is : After purchasing the watch, the remaining amount of Ali = 320 - 320 x 3/4 = 320 80 x 3 = € (320 -240) = €80 After purchasing the pen, remaining amount of Ali = 80 - 80 x 1/8 = 80 - 10 = €70

Let a # b # c # d=ab-cd. If x= 6 # 3 # 5 # 4, What is the value of 7 # x # 3 # 11 ?

Correct Answer Is : -47

Solution Is :

Q.In a class, there are 80 students who study both Computer Science and Electronics. While 100 students study Computer Science, 120 students study Electronics. How many of them study Computer Science only ?

Correct Answer Is : 20

Solution Is :

Q.In an examination, Rahul got the 11th rank and he was 47th from the bottom among those who passed 3 students could not appear from the exam. 1 student failed. What is the total number of students ?

Correct Answer Is : 61

Solution Is : Number of successful candidates = 11 + 47 - 1 = 57 Total number of students = 57 + 3 + 1 = 61.

Arrange the given dates of birth in descending chronology. 1. 15.04.1950 2. 14.05.1960 3. 14.06.1960 4. 20.04.1950 5. 25.05.1960

Correct Answer Is : 1, 4, 2, 5, 3

Solution Is :

Thetotal number of students in class A and class B is 120 . If 15 students from class A are taken and added to class B, the number in Class B becomes twice that of A. Find out the number of students in Class A in the beginning .

Correct Answer Is : 55

Solution Is : Suppose total number of students in class A = x Total number of students in class B = 120 -x Then , (120-x +15 ) = 2 ( x - 15 ) 135 - x = 2x - 30 3x = 165 x = 165 / 3 x = 55

Inf 5=5,6=12,7=21,8=32 ,then 9 is equal to

Correct Answer Is : 45

Solution Is : 5*1 = 5 6*2=12 7*3=21 8*4=32 9*5=45

Which among the following is a leap year?

Correct Answer Is : 1600

Solution Is : Centuries should be divided by 400 hence only 1600 is divided by 400 , hence 1600 is a leap year

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>Choose the similar group of numbers on the basis of certain common properties they Possess.
(72, 66, 96)

Solution Is : As. in (72, 66. 96). each number is divisible tx/ 6.
Similarly, in (55 66, 77), each number is divisible by 11

Solution Is : After purchasing the watch, the remaining amount of Ali
= 320 - 320 x 3/4 = 320 80 x 3 = € (320 -240) = €80
After purchasing the pen, remaining amount of Ali
= 80 - 80 x 1/8 = 80 - 10 = €70

Arrange the given dates of birth in descending chronology.
1. 15.04.1950
2. 14.05.1960
3. 14.06.1960
4. 20.04.1950
5. 25.05.1960

Solution Is : Suppose total number of students in class
A = x
Total number of students in class B = 120 -x
Then , (120-x +15 ) = 2 ( x - 15 )
135 - x = 2x - 30
3x = 165
x = 165 / 3
x = 55

Solution Is : 51 = 5
62=12
73=21
84=32
9*5=45