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SSC CHSL Exam SSC CHSL Quantative Aptitude Study Material

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Trigonometry

Three medians AD , BE and CF of a triangle ABC intersect at G . Area of triangle ABC is 108 sq cm . The area of triangle AGB is , ( in sq cm )

a) 54
b) 36
c) 48
d) 24

✔Answer

✔Solution

Correct Answer Is : 36

Solution Is :

In a triangle , distances from centroid to vertices are respectively 4 cm , 6 cm and 8 cm. Find medians .

a) 16cm , 4 cm , 18 cm
b) 4 cm , 6 cm , 8cm
c) 6cm , 9cm , 12cm
d) 20cm , 21cm , 25 cm

✔Answer

✔Solution

Correct Answer Is : 6cm , 9cm , 12cm

Solution Is :

A spherical ballon whose radius is r , subtends an angle ? at the eye of the observer on the ground . When the angle of elevation of its centre is ? . The height of its centre is

a) R cosec? sin?
b) R cosec(?/2) sin?
c) R cosec(?/2) cos?
d) R sin sin?

✔Answer

✔Solution

Correct Answer Is : R cosec(?/2) sin?

Solution Is :

If secθ + cosec (90o - θ) = 4 , ( 0<θ<90o), then the value of tanθ is

a) √3
b) 1/√2
c) 1/√3
d) 1

✔Answer

✔Solution

Correct Answer Is : √3

Solution Is :

The numerical values of - 9/cosec2θ + 4 cos2θ + 5 / (1+tan2θ) is

a) 4
b) 5
c) 9
d) 1

✔Answer

✔Solution

Correct Answer Is : 9

Solution Is :

An equilateral ?TQR is drawn inside a square PQRS. The value of the Angle PTS in degrees , is

a) 75°
b) 90°
c) 120°
d) 150°

✔Answer

✔Solution

Correct Answer Is : 150°

Solution Is :

If cosθ + secθ = 2 , the value of cos6θ + sec6θ is

a) 1
b) 2
c) 4
d) 8

✔Answer

✔Solution

Correct Answer Is : 2

Solution Is :

A man standing at appoint P is watching the top of a tower, which makes an angle of elevation of 30°.The man walks some distance towards the tower and then his angle of elevation of the top of the tower is 60°.If the height of the tower is 30m,then the distance he moves is

a) 20m
b) 20√3 m
c) 22m
d) 22√3m

✔Answer

✔Solution

Correct Answer Is : 20√3 m

Solution Is :

Thevalue of Cot 300 - Cot 75 0 / tan 15 0 - tan 60 0 is

a) -1
b) 0
c) 1
d) √3-1

✔Answer

✔Solution

Correct Answer Is : -1

Solution Is :

Thevalue of cotθ .tan(900- θ ) - sec(90o - θ)cosecθ + (sin2 25o + sin2 65o ) + √3 ( tan5o tan15o tan30o tan75o tan85o) is

a) 0
b) 1
c) -1
d) 2

✔Answer

✔Solution

Correct Answer Is : 1

Solution Is :

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SSC CHSL Exam SSC CHSL Quantative Aptitude Study Material

Trigonometry

Three medians AD , BE and CF of a triangle ABC intersect at G . Area of triangle ABC is 108 sq cm . The area of triangle AGB is , ( in sq cm )

Correct Answer Is : 36

Solution Is :

In a triangle , distances from centroid to vertices are respectively 4 cm , 6 cm and 8 cm. Find medians .

Correct Answer Is : 6cm , 9cm , 12cm

Solution Is :

A spherical ballon whose radius is r , subtends an angle ? at the eye of the observer on the ground . When the angle of elevation of its centre is ? . The height of its centre is

Correct Answer Is : R cosec(?/2) sin?

Solution Is :

If secθ + cosec (90o - θ) = 4 , ( 0<θ<90o), then the value of tanθ is

Correct Answer Is : √3

Solution Is :

The numerical values of - 9/cosec2θ + 4 cos2θ + 5 / (1+tan2θ) is

Correct Answer Is : 9

Solution Is :

An equilateral ?TQR is drawn inside a square PQRS. The value of the Angle PTS in degrees , is

Correct Answer Is : 150°

Solution Is :

If cosθ + secθ = 2 , the value of cos6θ + sec6θ is

Correct Answer Is : 2

Solution Is :

A man standing at appoint P is watching the top of a tower, which makes an angle of elevation of 30°.The man walks some distance towards the tower and then his angle of elevation of the top of the tower is 60°.If the height of the tower is 30m,then the distance he moves is

Correct Answer Is : 20√3 m

Solution Is :

Thevalue of Cot 300 - Cot 75 0 / tan 15 0 - tan 60 0 is

Correct Answer Is : -1

Solution Is :

Thevalue of cotθ .tan(900- θ ) - sec(90o - θ)cosecθ + (sin2 25o + sin2 65o ) + √3 ( tan5o tan15o tan30o tan75o tan85o) is

Correct Answer Is : 1

Solution Is :

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