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SSC CHSL Exam SSC CHSL Quantative Aptitude Study Material

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Mensuration

What is the ratio of the area of a right isosceles triangle inscribed in a circle to that of the area of the circle in which it is inscribed?

a) π
b) π/2
c) π/4
d) 1/π

✔Answer

✔Solution

Correct Answer Is : 1/π

Solution Is :

The relation between the side(s) of a metallic cube and the radius (r) of a sphere which can be cast from each other is expressed as

a) R²=S²?4π
b) R/S² = ?(S.4π/3
c) RS= ?(3/4π)
d) R=S ?(3/4π)

✔Answer

✔Solution

Correct Answer Is : R=S ?(3/4π)

Solution Is :

The formula for the number of the diagonals in a polygon of n sides is d=1/2[n(n-3)]. If the number of diagonals in a polygon is twice the number of sides, then what is the number of sides?

a) 3
b) 5
c) 7
d) 8

✔Answer

✔Solution

Correct Answer Is : 7

Solution Is : (C ) The formula for the number of the diagonals in a polygon of n sides is d=1/2[n(n-3)]. If the number of diagonals in a polygon is twice the number of sides, then the number of sides are 7 .

The height of a room is 5 m and capacity is 500 cu. m. If the room is a square, then how much paper of two-meter width is required to cover the walls?

a) 120 m
b) 90 m
c) 100 m
d) 60 m

✔Answer

✔Solution

Correct Answer Is : 100 m

Solution Is : Required Width is 100m

The diagonals of a rhombus are 45 and 30.The area of the rhombus is

a) 675
b) 1350
c) 2700
d) 2010

✔Answer

✔Solution

Correct Answer Is : 675

Solution Is : (A) Area of Rhombus = 1/2 ( Product of diagonals) = 1/2(45*30) =675

The diagonal of a rhombus is 8 m and 6 m respectively. Find its area.

a) 48 sq m
b) 24 sq m
c) 12 sq m
d) 96 sq m

✔Answer

✔Solution

Correct Answer Is : 24 sq m

Solution Is : Area of rhombus = product of diagonals /2 = 8x6 /2 = 48/2 = 24 sq m .

If angles of a quadrilateral are in the ratio 3 : 5 : 9 : 13. Find the largest angle?

a) 155
b) 170
c) 156
d) 150

✔Answer

✔Solution

Correct Answer Is : 156

Solution Is : Sum of angles of a quadrilateral is 360 . Angles are in the ratio 3 : 5 : 9 : 13 . Sum of the angles = 360 3x + 5x + 9x + 13 x = 360 30 x = 360 x = 12 Largest angle is 13x = 13 * 12 = 156

The perimeter of a rectangle is 28 cm. If the length is 5 / 2 times its breadth, find the length and breadth of the rectangle.

a) 9 & 5
b) 10 & 4
c) 6 & 7
d) 11 & 3

✔Answer

✔Solution

Correct Answer Is : 10 & 4

Solution Is : Perimeter of rectangle = 28 2 ( l+b) = 28 Given length is 5/2 of breadth l = (5/2) b ---> 2 ( 5b/2 + b ) = 28 2 ( 7b/2) = 28 7b = 28 b = 4 l = 5/2 x b l = 10

If the edge of a cube is increased by increased by 100% then the surface area of the cube is increased by

a) 100%
b) 200%
c) 300%
d) 400%

✔Answer

✔Solution

Correct Answer Is : 300%

Solution Is : The required surface area increased =[(100+x/100)²-1]100% =[(100+100/100)²-1]100% =[(200/100)²-1]100 =[(2)²-1]100% =(4-1)*100% =300%

The area of the shaded region in the given figure is

a) A²(π-1)Sq units
b) (a²/2)(π-2)Sq units
c) A²(π-2)Sq units
d) (a²/2)(π-1)Sq units

✔Answer

✔Solution

Correct Answer Is : (a²/2)(π-2)Sq units

Solution Is :

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SSC CHSL Exam SSC CHSL Quantative Aptitude Study Material

Mensuration

What is the ratio of the area of a right isosceles triangle inscribed in a circle to that of the area of the circle in which it is inscribed?

Correct Answer Is : 1/π

Solution Is :

The relation between the side(s) of a metallic cube and the radius (r) of a sphere which can be cast from each other is expressed as

Correct Answer Is : R=S ?(3/4π)

Solution Is :

The formula for the number of the diagonals in a polygon of n sides is d=1/2[n(n-3)]. If the number of diagonals in a polygon is twice the number of sides, then what is the number of sides?

Correct Answer Is : 7

Solution Is : (C ) The formula for the number of the diagonals in a polygon of n sides is d=1/2[n(n-3)]. If the number of diagonals in a polygon is twice the number of sides, then the number of sides are 7 .

The height of a room is 5 m and capacity is 500 cu. m. If the room is a square, then how much paper of two-meter width is required to cover the walls?

Correct Answer Is : 100 m

Solution Is : Required Width is 100m

The diagonals of a rhombus are 45 and 30.The area of the rhombus is

Correct Answer Is : 675

Solution Is : (A) Area of Rhombus = 1/2 ( Product of diagonals) = 1/2(45*30) =675

The diagonal of a rhombus is 8 m and 6 m respectively. Find its area.

Correct Answer Is : 24 sq m

Solution Is : Area of rhombus = product of diagonals /2 = 8x6 /2 = 48/2 = 24 sq m .

If angles of a quadrilateral are in the ratio 3 : 5 : 9 : 13. Find the largest angle?

Correct Answer Is : 156

Solution Is : Sum of angles of a quadrilateral is 360 . Angles are in the ratio 3 : 5 : 9 : 13 . Sum of the angles = 360 3x + 5x + 9x + 13 x = 360 30 x = 360 x = 12 Largest angle is 13x = 13 * 12 = 156

The perimeter of a rectangle is 28 cm. If the length is 5 / 2 times its breadth, find the length and breadth of the rectangle.

Correct Answer Is : 10 & 4

Solution Is : Perimeter of rectangle = 28 2 ( l+b) = 28 Given length is 5/2 of breadth l = (5/2) b ---> 2 ( 5b/2 + b ) = 28 2 ( 7b/2) = 28 7b = 28 b = 4 l = 5/2 x b l = 10

If the edge of a cube is increased by increased by 100% then the surface area of the cube is increased by

Correct Answer Is : 300%

Solution Is : The required surface area increased =[(100+x/100)2-1]*100% =[(100+100/100)2-1]*100% =[(200/100)2-1]*100 =[(2)2-1]*100% =(4-1)*100% =300%

The area of the shaded region in the given figure is

Correct Answer Is : (a2/2)(π-2)Sq units

Solution Is :

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Solution Is : The required surface area increased =[(100+x/100)²-1]100% =[(100+100/100)²-1]100% =[(200/100)²-1]100 =[(2)²-1]100% =(4-1)*100% =300%

Correct Answer Is : (a²/2)(π-2)Sq units