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  • SBI SO Exam Quantitative Aptitude Study Material

Digitization help student to explore and study their academic courses online, as this gives them flexibility and scheduling their learning at their convenience. Kidsfront has prepared unique course material of Quantitative Aptitude Pipes and Cisterns for SBI SO Exam student. This free online Quantitative Aptitude study material for SBI SO Exam will help students in learning and doing practice on Pipes and Cisterns topic of SBI SO Exam Quantitative Aptitude . The study material on Pipes and Cisterns, help SBI SO Exam Quantitative Aptitude students to learn every aspect of Pipes and Cisterns and prepare themselves for exams by doing online test exercise for Pipes and Cisterns, as their study progresses in class. Kidsfront provide unique pattern of learning Quantitative Aptitude with free online comprehensive study material and loads of SBI SO Exam Quantitative Aptitude Pipes and Cisterns exercise prepared by the highly professionals team. Students can understand Pipes and Cisterns concept easily and consolidate their learning by doing practice test on Pipes and Cisterns regularly till they excel in Quantitative Aptitude Pipes and Cisterns.


Pipes and Cisterns
A water tank can be filled by a tap in 10 minutes and another tap can be filled it in 60 minutes. If both the taps are kept open for 5 minutes and then the first tap is closed, how long will it take for the tank to be full?

a) 45 minutes
b) 30 minutes
c) 25 minutes
d) 20 minutes



Answer
Solution
Correct Answer Is : 45 minutes
Solution Is :
Two pipes can fill a cistern in 6 mins and 7 minutes respectively. Both the pipe are opened alternately for 1 minute each. In what time will they fill the cistern?

a) 5 minutes
b) 17/3minutes
c) 45/7 minutes
d) 5/4 minutes



Answer
Solution
Correct Answer Is : 45/7 minutes
Solution Is : It is an alternate men`s problem A` s 1 min work=(1/60) B` s 1 min work=(1/7) (A+B)`s 2 min work=(1/6)+(1/7)=13/42 (A+B)`s 6 min work=(3*13/42)=13/14 Remaining work =1-(13/14)=1/14 It is A` turn and 1/14 part to be filled Time taken to fill 1/14 part =(1/14)*6=(3/7)mins The time taken to fill the take=6mins+(3/7)mins =45/7 mins
Two pipes A and B can fill a tank with water in 30 minutes and 45 minutes respectively. The water pipe C can empty the tank in 36 minutes. First A and B are opened. After 12 minutes C is opened. Total time (in minutes) in which the tank will be filled up is :

a) 30
b) 12
c) 36
d) 24



Answer
Solution
Correct Answer Is : 24
Solution Is : Part of tank filled by pipes A and B in 1 minute = (1/30)-(1/45)=1/18 part.
Therefore,part of tank filled in 12 minutes=(12/15)=2/3 part
Remaning part=1-(2/3)=1/3 part
when pipe Cis opened,part of tank filled by all 3 pipes=(1/30)(1/45)-(1/36)=5/180=1/36.
therefore,Time taken in filling 1/3 part = (1/3)*36=12 minutes,
therefore,Total time=12+12 =24 minutes.
Pipe A can fill a tank in 4 hours and pipe B can fill it in 6 hours. If they are opened on alternate hours and if pipe A is opened first, in how many hours, the tank shall be full ?

a) 4 1/2
b) 3 1/2
c) 3 1/4
d) 4 2/3



Answer
Solution
Correct Answer Is : 4 2/3
Solution Is : Part of tank filled in first two hours = 1/4 + 1/6 = (3+2)/12 = 5/12. Part of tank filled I first 4 hours =10/12 =5/6. Remaining part 1 - 5/6 =1/6. This remaining part will be filled by pipe A. Time taken by Pipe A = (1/6) *4 = 2/3 hour. Therefore total time = 4+(2/3) = 4 2/3
Pipe A alone can fill a tank in 8 hours. Pipe B alone can fill it in 6 hours. If both the pipes are opened and after 2 hours pipe A is closed, then the other pipe will fill the tank in

a) 6 hours
b) 3.5 hours
c) 4 hours
d) 2.5 hours



Answer
Solution
Correct Answer Is : 2.5 hours
Solution Is :
Water is flowing at the rate of 5 km/h through a pipe of diameter 14 cm into a rectangular tank which is 50 m long, 44m wide. The time taken, in hours, for the rise in the level of water in the tank to be 7 cm is

a) 2
b) 1.5
c) 3
d) 2.5



Answer
Solution
Correct Answer Is : 2
Solution Is : diameter of pipe is 14cm or 14/100 m then radius is 7/100m water is flowing at rate of 5km/h or 5000m/h then water flow in 1h= (22*5000*7*7)/(7**100100) = 77 cube m rectangular tank is 50m long and 44m wide and height will be 7cm or 7/100m volume of tank= (50*44*7)/100 =154 cube m77cube m water take time to flow= 60minute 1 cube m water take time to flow= 60/77 minute 154 cube m water take time to flow= (60*154)/77 minute =120minuteor =2hour.
Water flows into a tank which is 200mlong and 150mwide, through a pipe of cross-section 0.3m × 0.2m at 20 km/hour. Then the time (in hour) for the water level in the tank to each 8cm is

a) 50
b) 120
c) 150
d) 200



Answer
Solution
Correct Answer Is : 200
Solution Is : Water supplied by pipe in 1 hour =(0.3 × 0.2 ×20 × 1000) cubicmeter = 1200 cubic metre Therefore Total time =( Volume of water to be filled in the tank )/1200 =(200 *150 * 8)/1200 = 200 hours
Two equal vessels are filled with the mixture ofwater and milk in the ratio of 3:4 and 5:3 respectively. If the mixtures are poured into a third vessel, the ratio of water and milk in the third vessel will be

a) 15:12
b) 53:59
c) 20:9
d) 59:53



Answer
Solution
Correct Answer Is : 59:53
Solution Is : Let the capacity of each vessel = 1 litre.
In First Vessel, Water= 3 /7 litre :Milk= 4/7 litre.
In Second Vessel, Water= 5 /8 litre ; Milk= 3/8 litre. In 2 litres of mixture, Water : milk
Therefore water : milk = 59 : 53
Pipe A is an inlet pipe filling the tank at 800 l/hr. Pipe B empties the tank in 3 hours. The capacity of the tank is

a) 12000 l
b) 8000 l
c) 6000 l
d) 4000 l



Answer
Solution
Correct Answer Is : 12000 l
Solution Is : Pipe A is an inlet pipe filling the tank at 800 l/hr. Pipe B empties the tank in 3 hours. The capacity of the tank is 1200 l
Two pipes, P and Q can fill a cistern in 12 and 15 minutes respectively. If both are opened together and at the end of 3 minutes, the first is closed, how much longer will the cistern take to fill?

a) 5minutes
b)
c)
d)



Answer
Solution
Correct Answer Is :
Solution Is :

Preparation for Exams

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