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INDIAN NAVY SAILORS Numerical Ability Study Material

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Geometry

In ?ABC , ?A = 30°,?B = 60°.Find ?c in circular measure

a) π°/6
b) π°/2
c) 2π°/3
d) 3π°/4

✔Answer

Correct Answer Is : π°/2

Solution Is :

An equation whose graph passes through the origin,out of the given equations 2X + 3Y=2 , 2X-3Y=3 , -2X+3Y=5 and 2X+3Y=0 is

a) 2X+3Y=2
b) 2X-3Y=3
c) FALSE
d) 2X+3Y=0

✔Answer

Correct Answer Is : 2X+3Y=0

Solution Is :

A unique circle can always be drawn through x number of given non-collinear points,then x must be

a) 1
b) 2
c) 3
d) 4

✔Answer

Correct Answer Is : 3

Solution Is :

If Triangle ABC is similar to Triangle DEF ,such that Angle A= 47° Angle E = 63°,then Angle C is equal to

a) 37°
b) 40°
c) 70°
d) 65°

✔Answer

Correct Answer Is : 70°

Solution Is :

Abcd is aquadrilateral inscribed in a circle with centre O.If Angle COD =120° and Angle BAC =30°, then Angle BCD is

a) 60°
b) 75°
c) 90°
d) 120°

✔Answer

Correct Answer Is : 90°

Solution Is :

ABCD is a trapezium whose side AD is parallel to BC,Diagonals AC and BD Intersect at o.if AO=3,CO=x-3,Bo=3x-19 and DO=x-5,the value (s) of x will be

a) 8,9
b) 7,6
c) 12,6
d) 7,10

✔Answer

Correct Answer Is : 8,9

Solution Is :

There are two temples ,one on each bank of a river just opposite to each other .one temple is 54 m high.From the top of this temple ,the angles of depression of the top and the foot of the other temple are 300 and 60 0 ,respectively .The height of the temple is

a) 18√3 m
b) 18m
c) 36m
d) 36√3 m

✔Answer

Correct Answer Is : 36m

Solution Is :

Thelength of the shadow of a vertical tower on level ground increases by 10 m when the altitude of the sun changes from 45o to 30o Then the height of the tower is

a) 10(√3+1)m
b) 5(√3+1)m
c) 10√3m
d) 5√3m

✔Answer

Correct Answer Is : 5(√3+1)m

Solution Is :

If 5 tanθ=4,then 5sin θ-3cos θ/5 sinθ+ 2cosθ is equal to

a) 1/4
b) 1/6
c) 1/3
d) 2/3

✔Answer

Correct Answer Is : 1/6

Solution Is :

If x sinθ - y sinθ =√(x2+y2) and cos 2 θ/a2 ++ sin 2 θ/b2 =1 /x2 + y2 then the correct relation is

a) X2/a2 +y2/b2 = 1
b) X2/b2 +y2/a2 =1
c) X2/a2 - y2/ b2
d) X2/b2 -y2/a2 =1

✔Answer

Correct Answer Is : X2/b2 +y2/a2 =1

Solution Is :

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INDIAN NAVY SAILORS Numerical Ability Study Material

Geometry

In ?ABC , ?A = 30°,?B = 60°.Find ?c in circular measure

Correct Answer Is : π°/2

Solution Is :

An equation whose graph passes through the origin,out of the given equations 2X + 3Y=2 , 2X-3Y=3 , -2X+3Y=5 and 2X+3Y=0 is

Correct Answer Is : 2X+3Y=0

Solution Is :

A unique circle can always be drawn through x number of given non-collinear points,then x must be

Correct Answer Is : 3

Solution Is :

If Triangle ABC is similar to Triangle DEF ,such that Angle A= 47° Angle E = 63°,then Angle C is equal to

Correct Answer Is : 70°

Solution Is :

Abcd is aquadrilateral inscribed in a circle with centre O.If Angle COD =120° and Angle BAC =30°, then Angle BCD is

Correct Answer Is : 90°

Solution Is :

ABCD is a trapezium whose side AD is parallel to BC,Diagonals AC and BD Intersect at o.if AO=3,CO=x-3,Bo=3x-19 and DO=x-5,the value (s) of x will be

Correct Answer Is : 8,9

Solution Is :

There are two temples ,one on each bank of a river just opposite to each other .one temple is 54 m high.From the top of this temple ,the angles of depression of the top and the foot of the other temple are 300 and 60 0 ,respectively .The height of the temple is

Correct Answer Is : 36m

Solution Is :

Thelength of the shadow of a vertical tower on level ground increases by 10 m when the altitude of the sun changes from 45o to 30o Then the height of the tower is

Correct Answer Is : 5(√3+1)m

Solution Is :

If 5 tanθ=4,then 5sin θ-3cos θ/5 sinθ+ 2cosθ is equal to

Correct Answer Is : 1/6

Solution Is :

If x sinθ - y sinθ =√(x2+y2) and cos 2 θ/a2 ++ sin 2 θ/b2 =1 /x2 + y2 then the correct relation is

Correct Answer Is : X2/b2 +y2/a2 =1

Solution Is :

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