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IBPS PO CWE Exam Quantitative Aptitude Study Material

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Arithmetic Aptitude

If a, b, c be all positive integers, then the least positive value of a³+ b³ + c³ - 3abc is

a) 1
b) 2
c) 4
d) 3

✔Answer

✔Solution

Correct Answer Is : 4

Solution Is : 2a = a + b + a – b = 1 + d/c
c + s = 2ac = 1 Þ 2c = 1/a
2b = (a + b) – (a – b) = 1 - d/c
c – d = 2bc = b(1/a)
c2 – d2 = (c + d) (c - d) = 1.b/a = b/a

A pipe can fill a cistern in 9 hours. Due to leak in its bottom, the cistern fills up in 10 hours. If cistern is full, in how much time will it be emptied by the leak?

a) 70 hours
b) 80 hours
c) 90 hours
d) 100 hours

✔Answer

✔Solution

Correct Answer Is : 90 hours

Solution Is : Ratio of efficiency = Ratio of the
part of work completed per day
= 1/3:1/4:1/6
= 4 : 3 : 2
Amount will be shared in the ratio of respective time x efficiency, which is 7 ´ 4 : 8 ´ 3 : 10 ´ 2
= 7 : 6 : 5
Trained labour gets 7/7+6+5 ´ `369
= `7 ´20.5 = `143.5

The next term of the series 1, 5,12, 24, 43 is

a) 51
b) 62
c) 71
d) 78

✔Answer

✔Solution

Correct Answer Is : 71

Solution Is : The pattern is 1 + 4 = 5
5 + 7 (= 4 + 3) = 12
12 + 12 (= 7 + 5) = 24
24 + 19 (= 12 + 7) = 43
43 + 28 (=19 + 9)= 71

A container has 80 L of milk. From this container 8 L of milk was taken out and replaced by water. The process was further repeated twice. The volue of milk in the container after that is :

a) 85.32 L
b) 58.23 L
c) 85.23 L
d) 58.32 L

✔Answer

✔Solution

Correct Answer Is : 58.32 L

Solution Is :

Water is flowing at the rate of 3 km/hr through a circular pipe of 20 cm internal diameter into a circular cistern of diameter 10m and depth 2m. In how much time will the cistern be filled ?

a) 1 hour
b) 1 hour 40 minutes
c) 1 hour 20 minutes
d) 2 hours 40 minutes

✔Answer

✔Solution

Correct Answer Is : 1 hour 40 minutes

Solution Is :

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IBPS PO CWE Exam Quantitative Aptitude Study Material

Arithmetic Aptitude

If a, b, c be all positive integers, then the least positive value of a3+ b3 + c3 - 3abc is

Correct Answer Is : 4

Solution Is : 2a = a + b + a – b = 1 + d/c c + s = 2ac = 1 Þ 2c = 1/a 2b = (a + b) – (a – b) = 1 - d/c c – d = 2bc = b(1/a) c2 – d2 = (c + d) (c - d) = 1.b/a = b/a

A pipe can fill a cistern in 9 hours. Due to leak in its bottom, the cistern fills up in 10 hours. If cistern is full, in how much time will it be emptied by the leak?

Correct Answer Is : 90 hours

Solution Is : Ratio of efficiency = Ratio of the part of work completed per day = 1/3:1/4:1/6 = 4 : 3 : 2 Amount will be shared in the ratio of respective time x efficiency, which is 7 ´ 4 : 8 ´ 3 : 10 ´ 2 = 7 : 6 : 5 Trained labour gets 7/7+6+5 ´ `369 = `7 ´20.5 = `143.5

The next term of the series 1, 5,12, 24, 43 is

Correct Answer Is : 71

Solution Is : The pattern is 1 + 4 = 5 5 + 7 (= 4 + 3) = 12 12 + 12 (= 7 + 5) = 24 24 + 19 (= 12 + 7) = 43 43 + 28 (=19 + 9)= 71

Correct Answer Is :

Solution Is :

What would be the sum of 1+3+5+7+9+ 11+ 13+15 + ………….up to 15th term?

Correct Answer Is : 225

Solution Is :

If 13 + 23 + + 93 = 2025, then the approximate value of (0.11) + (0.22) + …………… + (0.99) is

Correct Answer Is : 2.695

Solution Is :

Pipe A alone can fill a tank in 8 hours. Pipe B alone can fill it in 6 hours. If both the pipes are opened and after 2 hours pipe A is closed, then the other pipe will fill the tank in

Correct Answer Is : 2.5 hours

Solution Is :

The odd element in the sequence 3, 7, 13, 21, 33, 43, 57, _is :

Correct Answer Is : 33

Solution Is : (2) The pattern is: 3+4=7 7+6=13 13+8=21 21+10=30?33 31+12=43

A container has 80 L of milk. From this container 8 L of milk was taken out and replaced by water. The process was further repeated twice. The volue of milk in the container after that is :

Correct Answer Is : 58.32 L

Solution Is :

Water is flowing at the rate of 3 km/hr through a circular pipe of 20 cm internal diameter into a circular cistern of diameter 10m and depth 2m. In how much time will the cistern be filled ?

Correct Answer Is : 1 hour 40 minutes

Solution Is :

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If a, b, c be all positive integers, then the least positive value of a³+ b³ + c³ - 3abc is

Solution Is : 2a = a + b + a – b = 1 + d/c
c + s = 2ac = 1 Þ 2c = 1/a
2b = (a + b) – (a – b) = 1 - d/c
c – d = 2bc = b(1/a)
c2 – d2 = (c + d) (c - d) = 1.b/a = b/a

Solution Is : Ratio of efficiency = Ratio of the
part of work completed per day
= 1/3:1/4:1/6
= 4 : 3 : 2
Amount will be shared in the ratio of respective time x efficiency, which is 7 ´ 4 : 8 ´ 3 : 10 ´ 2
= 7 : 6 : 5
Trained labour gets 7/7+6+5 ´ `369
= `7 ´20.5 = `143.5

Solution Is : The pattern is 1 + 4 = 5
5 + 7 (= 4 + 3) = 12
12 + 12 (= 7 + 5) = 24
24 + 19 (= 12 + 7) = 43
43 + 28 (=19 + 9)= 71

Solution Is : (2) The pattern is:
3+4=7
7+6=13
13+8=21
21+10=30?33
31+12=43