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• #### Delhi Police Exam Reasoning Study Material

Digitization help student to explore and study their academic courses online, as this gives them flexibility and scheduling their learning at their convenience. Kidsfront has prepared unique course material of Reasoning Classification for Delhi Police Exam student. This free online Reasoning study material for Delhi Police Exam will help students in learning and doing practice on Classification topic of Delhi Police Exam Reasoning. The study material on Classification, help Delhi Police Exam Reasoning students to learn every aspect of Classification and prepare themselves for exams by doing online test exercise for Classification, as their study progresses in class. Kidsfront provide unique pattern of learning Reasoning with free online comprehensive study material and loads of Delhi Police Exam Reasoning Classification exercise prepared by the highly professionals team. Students can understand Classification concept easily and consolidate their learning by doing practice test on Classification regularly till they excel in Reasoning Classification.

a) ACB
b) GIH
c) MON
d) PQR

a) BYCX
b) EVFU
c) GTHS
d) LOIR

a) 35
b) 64
c) 28
d) 84

a) 515-103
b) 635-127
c) 745-149
d) 856-214

a) 827
b) 518
c) 829
d) 748

a) 347
b) 518
c) 829
d) 748

a) 827
b) 347
c) 283
d) 748

a) 518
b) 748
c) 827
d) 829

a) 518
b) 827
c) 829
d) 347

a) 283 and 518
b) 347 and 748
c) 283 and 827
d) 518 and 829

##### Solution Is : By doing asked in the question the numbers become 392, 753, 825, 938, 857, and 738 Now total numerical value of 283, and 518 = 392+825=1217 of 347 and 748= 753+857=1610 of 283 and 827 =392+738=1130 of 518and 829 =825+938=1763 Thus the pair 518 and 829 has highest of its numerical value
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