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  • Delhi Police Exam Numerical Ability Study Material

Digitization help student to explore and study their academic courses online, as this gives them flexibility and scheduling their learning at their convenience. Kidsfront has prepared unique course material of Numerical Ability Weight Height Marks for Delhi Police Exam student. This free online Numerical Ability study material for Delhi Police Exam will help students in learning and doing practice on Weight Height Marks topic of Delhi Police Exam Numerical Ability. The study material on Weight Height Marks, help Delhi Police Exam Numerical Ability students to learn every aspect of Weight Height Marks and prepare themselves for exams by doing online test exercise for Weight Height Marks, as their study progresses in class. Kidsfront provide unique pattern of learning Numerical Ability with free online comprehensive study material and loads of Delhi Police Exam Numerical Ability Weight Height Marks exercise prepared by the highly professionals team. Students can understand Weight Height Marks concept easily and consolidate their learning by doing practice test on Weight Height Marks regularly till they excel in Numerical Ability Weight Height Marks.


Weight Height Marks
In a history examination, the average for the entire class was 80% marks. If 10% of the students scored 95 marks an 20 % scored 90 marks, then what were the average marks of the remaining students of the class?

a) 65.5
b) 85
c) 75
d) 72.5



Answer
Solution
Correct Answer Is : 75
Solution Is : (C ) Let the total number of students be 100. Therefore, Required be 100. = (80*100-10*95-20*90)/70 = (8000-950-1800)/70 =5250/70 = 75
Neha` s weight is 140% of Tina`s weight. Mina`s weight is 90% of weight. Lina weight twice as much as Tina. If Neha`s weight is x% of Mina`s weight then x is eqal to

a) 64 2/9
b) `77 7/9
c) 90
d) 128 4/7



Answer
Solution
Correct Answer Is : `77 7/9
Solution Is :
A cricketer has a mean score of 60 runs in 10 innings. find out how many are runs to be scored in the eleventh innings to raise the mean score to 62?

a) 80
b) 81
c) 83
d) 82



Answer
Solution
Correct Answer Is : 82
Solution Is : Total runs scored in 10 innings = 60x10=600
lets runs scored in 11th innings = x
now total runs in 11 innings
600+x=11x62
600+x=682
x=682-600=82
In a history examination, the average for the entire class was 80% marks. If 10% of the students scored 95 marks an 20 % scored 90 marks, then what were the average marks of the remaining students of the class?

a) 65.5
b) 85
c) 75
d) 72.5



Answer
Solution
Correct Answer Is : 75
Solution Is : (C ) Let the total number of students be 100. Therefore, Required be 100. = (80*100-10*95-20*90)/70 = (8000-950-1800)/70 =5250/70 = 75
Neha` s weight is 140% of Tina`s weight. Mina`s weight is 90% of weight. Lina weight twice as much as Tina. If Neha`s weight is x% of Mina`s weight then x is eqal to

a) 64 2/9
b) `77 7/9
c) 90
d) 128 4/7



Answer
Solution
Correct Answer Is : `77 7/9
Solution Is :
A cricketer has a mean score of 60 runs in 10 innings. find out how many are runs to be scored in the eleventh innings to raise the mean score to 62?

a) 80
b) 81
c) 83
d) 82



Answer
Solution
Correct Answer Is : 82
Solution Is : Total runs scored in 10 innings = 60x10=600
lets runs scored in 11th innings = x
now total runs in 11 innings
600+x=11x62
600+x=682
x=682-600=82
In a history examination, the average for the entire class was 80% marks. If 10% of the students scored 95 marks an 20 % scored 90 marks, then what were the average marks of the remaining students of the class?

a) 65.5
b) 85
c) 75
d) 72.5



Answer
Solution
Correct Answer Is : 75
Solution Is : (C ) Let the total number of students be 100. Therefore, Required be 100. = (80*100-10*95-20*90)/70 = (8000-950-1800)/70 =5250/70 = 75
Neha` s weight is 140% of Tina`s weight. Mina`s weight is 90% of weight. Lina weight twice as much as Tina. If Neha`s weight is x% of Mina`s weight then x is eqal to

a) 64 2/9
b) `77 7/9
c) 90
d) 128 4/7



Answer
Solution
Correct Answer Is : `77 7/9
Solution Is :
A cricketer has a mean score of 60 runs in 10 innings. find out how many are runs to be scored in the eleventh innings to raise the mean score to 62?

a) 80
b) 81
c) 83
d) 82



Answer
Solution
Correct Answer Is : 82
Solution Is : Total runs scored in 10 innings = 60x10=600
lets runs scored in 11th innings = x
now total runs in 11 innings
600+x=11x62
600+x=682
x=682-600=82
In a history examination, the average for the entire class was 80% marks. If 10% of the students scored 95 marks an 20 % scored 90 marks, then what were the average marks of the remaining students of the class?

a) 65.5
b) 85
c) 75
d) 72.5



Answer
Solution
Correct Answer Is : 75
Solution Is : (C ) Let the total number of students be 100. Therefore, Required be 100. = (80*100-10*95-20*90)/70 = (8000-950-1800)/70 =5250/70 = 75

Preparation for Exams

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