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Delhi Police Exam Numerical Ability Study Material

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Numbers Operations

The sum of four consecutive even numbers is 748. The smallest among them is

a) 188
b) 186
c) 184
d) 174

✔Answer

✔Solution

Correct Answer Is : 184

Solution Is : (3) x+x+2+x+4+x+6 = 748 =>4x+12=748 =>4x=748-12=736 => x=736/4 = 184

a) 0.875
b) 0.733333333
c) 0.833333333
d) 0.666666667

✔Answer

✔Solution

Correct Answer Is : 0.875

Solution Is :

The next term of the sequence 1, 9, 28, 65, 126,

a) 199
b) 205
c) 216
d) 217

✔Answer

✔Solution

Correct Answer Is : 217

Solution Is : (4) The pattern of the sequence is : 1+2^3 = 9 1+3^3 = 28 1+4^3 = 65 1+5^3 = 126 1+6^3 = 217

If A:B= 3 : 4 and B:C= 6 : 5, then A : (A + C) is equal to

a) 9 : 10
b) 10 : 9
c) 9 : 19
d) 19 : 9

✔Answer

✔Solution

Correct Answer Is : 9 : 19

Solution Is :

If 2/3 of A = 75% of B = 0.6 of C, then A : B : C is equal to

a) 9 : 8 : 10
b) 8 : 9 : 10
c) 3 : 4 : 5
d) 4 : 3 : 5

✔Answer

✔Solution

Correct Answer Is : 9 : 8 : 10

Solution Is :

Working efficiencies of P and Q for completing a piece of work are in the ratio 3 : 4. The number of days to be taken by them to complete the work will be in the ratio

a) 3 : 2
b) 2 : 3
c) 3 : 4
d) 4 : 3

✔Answer

✔Solution

Correct Answer Is : 4 : 3

Solution Is : (4) Efficiency and time taken are inversely proportional. Required ratio= 4:3

If the sum of five consecutive integers is S, then the largest of those integers in terms of S is

a) (S-10)/5
b) (S+4)/4
c) (S+5)/4
d) (S+10)/5

✔Answer

✔Solution

Correct Answer Is : (S+10)/5

Solution Is : Let the five consecutive integers be x , x+1 , x+2 , x+3 and x+4 Then , x + x + 1 +x + 2 +x +3 +x +4 = S 5x + 10 = S x = ( S - 10 ) / 5 Largest integer is = x + 4 = (S -10) / 5 + 4 = S+10 /5

The greatest among the numbers 3√2 , 3√7 , 6√5 , 2√20 is

a) 3√2
b) 3√7
c) 6√5
d) 2√20`

✔Answer

✔Solution

Correct Answer Is : 6√5

Solution Is : 3√2 = 3 x 1.414 = 4.242 3√7 = 3 x 2.645 = 7.935 6√5 = 6 x 2.236 = 13.416 2√20 = 2 x 4.472 = 8.944

The denomenator of a fraction is 3 more than its numerator. If the numerator is increased by 7 and the denomenator is decreased by 2, we obtain 2. the sum of the numerator and denominator of the fraction is

a) 5
b) 13
c) 17
d) 19

✔Answer

✔Solution

Correct Answer Is : 13

Solution Is : Suppose, numerator of the fraction = x Denomenator of the fraction = x + 3 Then, (x+7)/(x+3-2) = 2 x+7 = 2(x+1) x = 5 Denominator of the fraction = 5+3 = 8 Hence required sum = 5 + 8 = 13

47 is added to the product of 71 and an unknown number .The new number is divisible by 7, giving the quotient 98. The unknown number is a multiple of

a) 2
b) 5
c) 7
d) 3

✔Answer

✔Solution

Correct Answer Is : 3

Solution Is : Suppose , unknown number = x Then , (x*71+47)/7 = 98 71x = 686 - 47 x = 639 / 7 = 9 3x3 = 9 Therefore , unknown number is divisible by 3.

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Delhi Police Exam Numerical Ability Study Material

Numbers Operations

The sum of four consecutive even numbers is 748. The smallest among them is

Correct Answer Is : 184

Solution Is : (3) x+x+2+x+4+x+6 = 748 =>4x+12=748 =>4x=748-12=736 => x=736/4 = 184

Correct Answer Is : 0.875

Solution Is :

The next term of the sequence 1, 9, 28, 65, 126,

Correct Answer Is : 217

Solution Is : (4) The pattern of the sequence is : 1+2^3 = 9 1+3^3 = 28 1+4^3 = 65 1+5^3 = 126 1+6^3 = 217

If A:B= 3 : 4 and B:C= 6 : 5, then A : (A + C) is equal to

Correct Answer Is : 9 : 19

Solution Is :

If 2/3 of A = 75% of B = 0.6 of C, then A : B : C is equal to

Correct Answer Is : 9 : 8 : 10

Solution Is :

Working efficiencies of P and Q for completing a piece of work are in the ratio 3 : 4. The number of days to be taken by them to complete the work will be in the ratio

Correct Answer Is : 4 : 3

Solution Is : (4) Efficiency and time taken are inversely proportional. Required ratio= 4:3

If the sum of five consecutive integers is S, then the largest of those integers in terms of S is

Correct Answer Is : (S+10)/5

Solution Is : Let the five consecutive integers be x , x+1 , x+2 , x+3 and x+4 Then , x + x + 1 +x + 2 +x +3 +x +4 = S 5x + 10 = S x = ( S - 10 ) / 5 Largest integer is = x + 4 = (S -10) / 5 + 4 = S+10 /5

The greatest among the numbers 3√2 , 3√7 , 6√5 , 2√20 is

Correct Answer Is : 6√5

Solution Is : 3√2 = 3 x 1.414 = 4.242 3√7 = 3 x 2.645 = 7.935 6√5 = 6 x 2.236 = 13.416 2√20 = 2 x 4.472 = 8.944

The denomenator of a fraction is 3 more than its numerator. If the numerator is increased by 7 and the denomenator is decreased by 2, we obtain 2. the sum of the numerator and denominator of the fraction is

Correct Answer Is : 13

Solution Is : Suppose, numerator of the fraction = x Denomenator of the fraction = x + 3 Then, (x+7)/(x+3-2) = 2 x+7 = 2(x+1) x = 5 Denominator of the fraction = 5+3 = 8 Hence required sum = 5 + 8 = 13

47 is added to the product of 71 and an unknown number .The new number is divisible by 7, giving the quotient 98. The unknown number is a multiple of

Correct Answer Is : 3

Solution Is : Suppose , unknown number = x Then , (x*71+47)/7 = 98 71x = 686 - 47 x = 639 / 7 = 9 3x3 = 9 Therefore , unknown number is divisible by 3.

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