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SBI PO Exam Quantitative Aptitude Study Material

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Pipes and Cisterns

A water tank can be filled by a tap in 10 minutes and another tap can be filled it in 60 minutes. If both the taps are kept open for 5 minutes and then the first tap is closed, how long will it take for the tank to be full?

a) 20 minutes
b) 25 minutes
c) 30 minutes
d) 45 minutes

✔Answer

✔Solution

Correct Answer Is : 45 minutes

Solution Is :

Two pipes can fill a cistern in 6 mins and 7 minutes respectively. Both the pipe are opened alternately for 1 minute each. In what time will they fill the cistern?

a) 5 minutes
b) 17/3minutes
c) 45/7 minutes
d) 5/4 minutes

✔Answer

✔Solution

Correct Answer Is : 45/7 minutes

Solution Is : It is an alternate men`s problem A` s 1 min work=(1/60) B` s 1 min work=(1/7) (A+B)`s 2 min work=(1/6)+(1/7)=13/42 (A+B)`s 6 min work=(313/42)=13/14 Remaining work =1-(13/14)=1/14 It is A` turn and 1/14 part to be filled Time taken to fill 1/14 part =(1/14)6=(3/7)mins The time taken to fill the take=6mins+(3/7)mins =45/7 mins

Two pipes A and B can fill a tank with water in 30 minutes and 45 minutes respectively. The water pipe C can empty the tank in 36 minutes. First A and B are opened. After 12 minutes C is opened. Total time (in minutes) in which the tank will be filled up is :

a) 30
b) 12
c) 36
d) 24

✔Answer

✔Solution

Correct Answer Is : 24

Solution Is : Part of tank filled by pipes A and B in 1 minute = (1/30)-(1/45)=1/18 part.
Therefore,part of tank filled in 12 minutes=(12/15)=2/3 part
Remaning part=1-(2/3)=1/3 part
when pipe Cis opened,part of tank filled by all 3 pipes=(1/30)(1/45)-(1/36)=5/180=1/36.
therefore,Time taken in filling 1/3 part = (1/3)*36=12 minutes,
therefore,Total time=12+12 =24 minutes.

Pipe A can fill a tank in 4 hours and pipe B can fill it in 6 hours. If they are opened on alternate hours and if pipe A is opened first, in how many hours, the tank shall be full ?

a) 4 1/2
b) 3 1/2
c) 3 1/4
d) 4 2/3

✔Answer

✔Solution

Correct Answer Is : 4 2/3

Solution Is : Part of tank filled in first two hours = 1/4 + 1/6 = (3+2)/12 = 5/12. Part of tank filled I first 4 hours =10/12 =5/6. Remaining part 1 - 5/6 =1/6. This remaining part will be filled by pipe A. Time taken by Pipe A = (1/6) *4 = 2/3 hour. Therefore total time = 4+(2/3) = 4 2/3

Pipe A alone can fill a tank in 8 hours. Pipe B alone can fill it in 6 hours. If both the pipes are opened and after 2 hours pipe A is closed, then the other pipe will fill the tank in

a) 6 hours
b) 3.5 hours
c) 4 hours
d) 2.5 hours

✔Answer

✔Solution

Correct Answer Is : 2.5 hours

Solution Is :

Water is flowing at the rate of 5 km/h through a pipe of diameter 14 cm into a rectangular tank which is 50 m long, 44m wide. The time taken, in hours, for the rise in the level of water in the tank to be 7 cm is

a) 2
b) 1.5
c) 3
d) 2.5

✔Answer

✔Solution

Correct Answer Is : 2

Solution Is : diameter of pipe is 14cm or 14/100 m then radius is 7/100m water is flowing at rate of 5km/h or 5000m/h then water flow in 1h= (2250007*7)/(7**100100) = 77 cube m rectangular tank is 50m long and 44m wide and height will be 7cm or 7/100m volume of tank= (50447)/100 =154 cube m77cube m water take time to flow= 60minute 1 cube m water take time to flow= 60/77 minute 154 cube m water take time to flow= (60*154)/77 minute =120minuteor =2hour.

Water flows into a tank which is 200mlong and 150mwide, through a pipe of cross-section 0.3m × 0.2m at 20 km/hour. Then the time (in hour) for the water level in the tank to each 8cm is

a) 50
b) 120
c) 150
d) 200

✔Answer

✔Solution

Correct Answer Is : 200

Solution Is : Water supplied by pipe in 1 hour =(0.3 × 0.2 ×20 × 1000) cubicmeter = 1200 cubic metre Therefore Total time =( Volume of water to be filled in the tank )/1200 =(200 150 8)/1200 = 200 hours

Two equal vessels are filled with the mixture ofwater and milk in the ratio of 3:4 and 5:3 respectively. If the mixtures are poured into a third vessel, the ratio of water and milk in the third vessel will be

a) 15:12
b) 53:59
c) 20:9
d) 59:53

✔Answer

✔Solution

Correct Answer Is : 59:53

Solution Is : Let the capacity of each vessel = 1 litre.
In First Vessel, Water= 3 /7 litre :Milk= 4/7 litre.
In Second Vessel, Water= 5 /8 litre ; Milk= 3/8 litre. In 2 litres of mixture, Water : milk
Therefore water : milk = 59 : 53

Pipe A is an inlet pipe filling the tank at 800 l/hr. Pipe B empties the tank in 3 hours. The capacity of the tank is

a) 12000 l
b) 8000 l
c) 6000 l
d) 4000 l

✔Answer

✔Solution

Correct Answer Is : 12000 l

Solution Is : Pipe A is an inlet pipe filling the tank at 800 l/hr. Pipe B empties the tank in 3 hours. The capacity of the tank is 1200 l

Two pipes, P and Q can fill a cistern in 12 and 15 minutes respectively. If both are opened together and at the end of 3 minutes, the first is closed, how much longer will the cistern take to fill?

a) 5minutes
b)
c)
d)

✔Answer

✔Solution

SBI PO Exam Quantitative Aptitude Study Material

Pipes and Cisterns

A water tank can be filled by a tap in 10 minutes and another tap can be filled it in 60 minutes. If both the taps are kept open for 5 minutes and then the first tap is closed, how long will it take for the tank to be full?

Correct Answer Is : 45 minutes

Solution Is :

Two pipes can fill a cistern in 6 mins and 7 minutes respectively. Both the pipe are opened alternately for 1 minute each. In what time will they fill the cistern?

Correct Answer Is : 45/7 minutes

Two pipes A and B can fill a tank with water in 30 minutes and 45 minutes respectively. The water pipe C can empty the tank in 36 minutes. First A and B are opened. After 12 minutes C is opened. Total time (in minutes) in which the tank will be filled up is :

Correct Answer Is : 24

Pipe A can fill a tank in 4 hours and pipe B can fill it in 6 hours. If they are opened on alternate hours and if pipe A is opened first, in how many hours, the tank shall be full ?

Correct Answer Is : 4 2/3

Solution Is : Part of tank filled in first two hours = 1/4 + 1/6 = (3+2)/12 = 5/12. Part of tank filled I first 4 hours =10/12 =5/6. Remaining part 1 - 5/6 =1/6. This remaining part will be filled by pipe A. Time taken by Pipe A = (1/6) *4 = 2/3 hour. Therefore total time = 4+(2/3) = 4 2/3

Pipe A alone can fill a tank in 8 hours. Pipe B alone can fill it in 6 hours. If both the pipes are opened and after 2 hours pipe A is closed, then the other pipe will fill the tank in

Correct Answer Is : 2.5 hours

Solution Is :

Water is flowing at the rate of 5 km/h through a pipe of diameter 14 cm into a rectangular tank which is 50 m long, 44m wide. The time taken, in hours, for the rise in the level of water in the tank to be 7 cm is

Correct Answer Is : 2

Water flows into a tank which is 200mlong and 150mwide, through a pipe of cross-section 0.3m × 0.2m at 20 km/hour. Then the time (in hour) for the water level in the tank to each 8cm is

Correct Answer Is : 200

Solution Is : Water supplied by pipe in 1 hour =(0.3 × 0.2 ×20 × 1000) cubicmeter = 1200 cubic metre Therefore Total time =( Volume of water to be filled in the tank )/1200 =(200 *150 * 8)/1200 = 200 hours

Two equal vessels are filled with the mixture ofwater and milk in the ratio of 3:4 and 5:3 respectively. If the mixtures are poured into a third vessel, the ratio of water and milk in the third vessel will be

Correct Answer Is : 59:53

Solution Is : Let the capacity of each vessel = 1 litre. In First Vessel, Water= 3 /7 litre :Milk= 4/7 litre. In Second Vessel, Water= 5 /8 litre ; Milk= 3/8 litre. In 2 litres of mixture, Water : milk Therefore water : milk = 59 : 53

Pipe A is an inlet pipe filling the tank at 800 l/hr. Pipe B empties the tank in 3 hours. The capacity of the tank is

Correct Answer Is : 12000 l

Solution Is : Pipe A is an inlet pipe filling the tank at 800 l/hr. Pipe B empties the tank in 3 hours. The capacity of the tank is 1200 l

Two pipes, P and Q can fill a cistern in 12 and 15 minutes respectively. If both are opened together and at the end of 3 minutes, the first is closed, how much longer will the cistern take to fill?

Correct Answer Is :

Solution Is :

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Solution Is : Water supplied by pipe in 1 hour =(0.3 × 0.2 ×20 × 1000) cubicmeter = 1200 cubic metre Therefore Total time =( Volume of water to be filled in the tank )/1200 =(200 150 8)/1200 = 200 hours

Solution Is : Let the capacity of each vessel = 1 litre.
In First Vessel, Water= 3 /7 litre :Milk= 4/7 litre.
In Second Vessel, Water= 5 /8 litre ; Milk= 3/8 litre. In 2 litres of mixture, Water : milk
Therefore water : milk = 59 : 53