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  • SBI PO Exam Quantitative Aptitude Study Material

Digitization help student to explore and study their academic courses online, as this gives them flexibility and scheduling their learning at their convenience. Kidsfront has prepared unique course material of Quantitative Aptitude Percentages for SBI PO Exam student. This free online Quantitative Aptitude study material for SBI PO Exam will help students in learning and doing practice on Percentages topic of SBI PO Exam Quantitative Aptitude. The study material on Percentages, help SBI PO Exam Quantitative Aptitude students to learn every aspect of Percentages and prepare themselves for exams by doing online test exercise for Percentages, as their study progresses in class. Kidsfront provide unique pattern of learning Quantitative Aptitude with free online comprehensive study material and loads of SBI PO Exam Quantitative Aptitude Percentages exercise prepared by the highly professionals team. Students can understand Percentages concept easily and consolidate their learning by doing practice test on Percentages regularly till they excel in Quantitative Aptitude Percentages.


Percentages
In a factory, the production of cycles rose to 48,400 from 40,000 in 2 years. The rate of growth per annum is

a) 9%
b) 8%
c) 10.50%
d) 10%



Answer
Solution
Correct Answer Is : 10%
Solution Is :
A number is increased by x%; to get back to the original number, it is to be reduced by

a) X%
b) 100x/100+x %
c) 10x/100+x %
d) X/ 100+x %



Answer
Solution
Correct Answer Is : 100x/100+x %
Solution Is :
In an examination 75% candidates passed in English and 60% passed in Mathematics. 25% failed in both and 240 passed the examination. Find the total number of candidates.

a) 492
b) 300
c) 500
d) 400



Answer
Solution
Correct Answer Is : 400
Solution Is : Failures in English = 100 - 75 = 25 Failures in Maths = 100 - 60 = 40 Failures in both subjects = 25 Failures in English only = 25 - 25 = 0 Failures in Maths only = 40 - 25 = 15 Failures in one or both subjects = 25 + 15 = 40 Percentages of successful = 100 - 40 = 60 Let total students be x. x * 60/100 = 240 x = 240 * 100/60 = 400
The difference between the value of the number increased by 20% and the value of the number decreased by 25% is 36. Find the number.

a) 7.2
b) 0.8
c) 720
d) 80



Answer
Solution
Correct Answer Is : 80
Solution Is : (4) Let the number be x. Therefore, (20+25) % of x =36 => 45x/100 = 36 => x = (36*100)/45 =80
The length of a rectangle is increased by 10% and breadth of a rectangle is decreased by 10%.The area of the new rectangle is

a) Neither increased nor decreased
b) Increased by 1%
c) Decreased by 2%
d) Decreased by 1%



Answer
Solution
Correct Answer Is : Decreased by 1%
Solution Is : (4) Change in area = (-10*10)/100 = -1 % Negative sign shows decrease.
In a factory, the production of cycles rose to 48,400 from 40,000 in 2 years. The rate of growth per annum is

a) 9%
b) 8%
c) 10.50%
d) 10%



Answer
Solution
Correct Answer Is : 10%
Solution Is :
A number is increased by x%; to get back to the original number, it is to be reduced by

a) X%
b) 100x/100+x %
c) 10x/100+x %
d) X/ 100+x %



Answer
Solution
Correct Answer Is : 100x/100+x %
Solution Is :
In an examination 75% candidates passed in English and 60% passed in Mathematics. 25% failed in both and 240 passed the examination. Find the total number of candidates.

a) 492
b) 300
c) 500
d) 400



Answer
Solution
Correct Answer Is : 400
Solution Is : Failures in English = 100 - 75 = 25 Failures in Maths = 100 - 60 = 40 Failures in both subjects = 25 Failures in English only = 25 - 25 = 0 Failures in Maths only = 40 - 25 = 15 Failures in one or both subjects = 25 + 15 = 40 Percentages of successful = 100 - 40 = 60 Let total students be x. x * 60/100 = 240 x = 240 * 100/60 = 400
The difference between the value of the number increased by 20% and the value of the number decreased by 25% is 36. Find the number.

a) 7.2
b) 0.8
c) 720
d) 80



Answer
Solution
Correct Answer Is : 80
Solution Is : (4) Let the number be x. Therefore, (20+25) % of x =36 => 45x/100 = 36 => x = (36*100)/45 =80
The length of a rectangle is increased by 10% and breadth of a rectangle is decreased by 10%.The area of the new rectangle is

a) Neither increased nor decreased
b) Increased by 1%
c) Decreased by 2%
d) Decreased by 1%



Answer
Solution
Correct Answer Is : Decreased by 1%
Solution Is : (4) Change in area = (-10*10)/100 = -1 % Negative sign shows decrease.
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