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  • IBPS SO CWE Exam Quantitative Aptitude Study Material

Digitization help student to explore and study their academic courses online, as this gives them flexibility and scheduling their learning at their convenience. Kidsfront has prepared unique course material of Quantitative Aptitude Mixture and Allegations for IBPS SO CWE Exam student. This free online Quantitative Aptitude study material for IBPS SO CWE Exam will help students in learning and doing practice on Mixture and Allegations topic of IBPS SO CWE Exam Quantitative Aptitude. The study material on Mixture and Allegations, help IBPS SO CWE Exam Quantitative Aptitude students to learn every aspect of Mixture and Allegations and prepare themselves for exams by doing online test exercise for Mixture and Allegations, as their study progresses in class. Kidsfront provide unique pattern of learning Quantitative Aptitude with free online comprehensive study material and loads of IBPS SO CWE Exam Quantitative Aptitude Mixture and Allegations exercise prepared by the highly professionals team. Students can understand Mixture and Allegations concept easily and consolidate their learning by doing practice test on Mixture and Allegations regularly till they excel in Quantitative Aptitude Mixture and Allegations.


Mixture and Allegations
A pipe can fill a tank in x hours and another can empty it in y hours. They can together fill it in (y > x )

a) X-y
b) Y-x
c) Xy/x-y
d) Xy/y-x


✔Answer
✔Solution
Correct Answer Is : Xy/y-x
Solution Is : Work done by A in one hour =1/x
work done by B in one hour=1/y
Both A and B together work in one hour=(1/x)-(1/y) =(y-x)/xy.
Both A and B fill tank in xy/(y-x) hours.
A tap can empty a tank in 30 minutes. A second tap can empty it in 45 minutes. If both the taps operate simultaneously, how much time is needed to empty the tank ?

a) 18 minutes
b) 14 minutes
c) 15 minutes
d) 30 minutes


✔Answer
✔Solution
Correct Answer Is : 18 minutes
Solution Is : Work done by 1st tap in one minute =1/30
work done by 2nd tap in one minute =1/45
Both taps one minute work =(1/30)+(1/45)
=(45+30)/1350
=75/1350 =1/18.
Both tap will empty the tank in 18 minutes.
729 ml of a mixture contains milk and water in the ratio 7 : 2. How much more water is to be added to get a new mixture containing milk and water in the ratio 7 : 3 ?

a) 60 ml
b) 71 ml
c) 52 ml
d) 81 ml


✔Answer
✔Solution
Correct Answer Is : 81 ml
Solution Is : Quantity of milk =(7/9) *729 =567ml
Quantity of water =(2/9)*729 =162ml
Let `x` be the quantity that should be added to make the ratio 7:3.
According to the question, 567/(162+x) =7/3
=>1701 =1134+7x
=> 7x =1701 -1134
=>x=81ml
A shopkeeper bought 30 kg of rice at the rate of Rs. 70 per kg and 20 kg of rice at the rate of Rs. 70.75 per kg. If he mixed the two brands of rice and sold the mixture at Rs. 80.50 per kg, his gain is

a) Rs. 510
b) Rs. 525
c) Rs. 485
d) Rs. 450


✔Answer
✔Solution
Correct Answer Is : Rs. 510
Solution Is :
Pipe A can fill a tank in 4 hours and pipe B can fill it in 6 hours. If they are opened on alternate hours and if pipe A is opened first, in how many hours, the tank shall be full ?

a) 4 1/2
b) 3 1/2
c) 3 1/4
d) 4 2/3


✔Answer
✔Solution
Correct Answer Is : 4 2/3
Solution Is : Part of tank filled in first two hours = 1/4 + 1/6 = (3+2)/12 = 5/12. Part of tank filled I first 4 hours =10/12 =5/6. Remaining part 1 - 5/6 =1/6. This remaining part will be filled by pipe A. Time taken by Pipe A = (1/6) *4 = 2/3 hour. Therefore total time = 4+(2/3) = 4 2/3
Two alloys contain tin and iron in the ratio of 1 : 2 and 2 : 3. If the two alloys are mixed in the proportion of 3 : 4 respectively (by weight), the ratio of tin and iron in the newly formed alloy is :

a) 10 : 21
b) 13 : 22
c) 14 : 25
d) 12 : 23



✔Answer
✔Solution
Correct Answer Is : 13 : 22
Solution Is : Let 3kg of first alloy and
4kg of second alloy could be mixed together.
Therefore, In 3kg of mixture,
Tin = 1kg
Iron = 2kg.
In 4kg of mixture,
Tin=(2/5)×4 = 8/5 kg=1.6kg
Iron=(3/5)×4=12/5=2.4kg
Therefore,Required ratio
=(1+1.6) : (2+2.4) =2.6 : 4.4
13 : 22
Two pipes A and B can fill a tank with water in 30 minutes and 45 minutes respectively. The water pipe C can empty the tank in 36 minutes. First A and B are opened. After 12 minutes C is opened. Total time (in minutes) in which the tank will be filled up is :

a) 30
b) 12
c) 36
d) 24


✔Answer
✔Solution
Correct Answer Is : 24
Solution Is : Part of tank filled by pipes A and B in 1 minute = (1/30)-(1/45)=1/18 part. Therefore,part of tank filled in 12 minutes=(12/15)=2/3 part Remaning part=1-(2/3)=1/3 part when pipe Cis opened,part of tank filled by all 3 pipes=(1/30)(1/45)-(1/36)=5/180=1/36. therefore,Time taken in filling 1/3 part = (1/3)*36=12 minutes, therefore,Total time=12+12 =24 minutes.
An empty pool being filled with water at a constant rate takes 8 hours to fill 3/5 th of its capacity. How much more time will it take to finish filling the pool ?

a) 4 hours 50 minutes
b) 5 hours 30 minutes
c) 5 hours 20 minutes
d) 4 hours 48 minutes


✔Answer
✔Solution
Correct Answer Is : 5 hours 20 minutes
Solution Is :
Pipe A is an inlet pipe filling the tank at 800 l/hr. Pipe B empties the tank in 3 hours. The capacity of the tank is

a) 12000 l
b) 8000 l
c) 6000 l
d) 4000 l


✔Answer
✔Solution
Correct Answer Is : 12000 l
Solution Is :
In what ration must 25% of alcohol be mixed with 50% of alcohol to get a mixture of 40% strent alcohol?

a) 1 : 2
b) 2 : 1
c) 2 : 3
d) 3 : 2


✔Answer
✔Solution
Correct Answer Is : 2 : 3
Solution Is : Given, 2. (r3) = 54 Þ r = 3
Two mean proportionals
= 2r & 2r2 = 2(3), 2(3)2
= 6, 18.

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