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  • Delhi Police Exam Numerical Ability Study Material

Digitization help student to explore and study their academic courses online, as this gives them flexibility and scheduling their learning at their convenience. Kidsfront has prepared unique course material of Numerical Ability Ratio and Proportion for Delhi Police Exam student. This free online Numerical Ability study material for Delhi Police Exam will help students in learning and doing practice on Ratio and Proportion topic of Delhi Police Exam Numerical Ability. The study material on Ratio and Proportion, help Delhi Police Exam Numerical Ability students to learn every aspect of Ratio and Proportion and prepare themselves for exams by doing online test exercise for Ratio and Proportion, as their study progresses in class. Kidsfront provide unique pattern of learning Numerical Ability with free online comprehensive study material and loads of Delhi Police Exam Numerical Ability Ratio and Proportion exercise prepared by the highly professionals team. Students can understand Ratio and Proportion concept easily and consolidate their learning by doing practice test on Ratio and Proportion regularly till they excel in Numerical Ability Ratio and Proportion.


Ratio and Proportion
The cost of making an article is divided between materials, labour and overheads in the ratio 3 : 4 : 1. If the material cost is 22.50₹, find the cost of the article ?

a) ₹100
b) ₹80
c) ₹60
d) ₹40


✔Answer
✔Solution
Correct Answer Is : ₹60
Solution Is : Let cost of article be x, Material : Labour : Overheads = 3 : 4 : 1 Cost of material = 22.50 3/( 3 + 4 + 1) x = 45/2 x = 45/2 * 8/3 = 60.
Divide 13,680 in three parts such that 1st part is 3/5 th of the third part and the ratio between 2 nd and 3 rd part is 4 : 7. How much is the first part?

a) 3780
b) 6300
c) 3600
d) 4800


✔Answer
✔Solution
Correct Answer Is : 3780
Solution Is : Let x , y ,z be 3 parts . Given x = (3/5) z ---> 5x = 3z y/z = 4 / 7 ---> 7y = 4z x + y +z = 13,680 --- ( eqn 1 ) x = 3z/5 y = 4z/7 Substitute value of x and y in equation 1 3z/5 + 4z/7 + z = 13,680 (21z + 20y + 35z ) / 35 = 13680 76 z = 13680 x 35 z = 13680 x 35 / 76 z = 6300 x = 3x 6300 / 5 x = 3,780
The ratio between the weights of gold and silver in an alloy is 17 : 3. If the weight of silver in the alloy is 2.7 gm, find the weight of gold in the alloy.

a) 12.6 gm
b) 15.3 gm
c) 18 gm
d) 21.2 gm


✔Answer
✔Solution
Correct Answer Is : 15.3 gm
Solution Is : Gold : Silver = 17 : 3 Let total weight of alloy be 20 x and weight of gold is 17x and silver 3x Given , weight of silver is = 2.7 g 3x = 2.7 g x = 0.9 g Weight of gold is , 17 x = 17 x 0.9 = 15.3 g
22 carat gold is mixed with 18 carat gold in the ratio 1:2 to get x carat gold. Then , the value of x is

a) 20
b) 15(2/3)
c) 14
d) 19(1/3)


✔Answer
✔Solution
Correct Answer Is : 19(1/3)
Solution Is :
The ratio between the rates of walking of A and B is 2:3.If the time taken by B to cover a certain distance is 36min the time taken by A to cover that much distance is

a) 24min
b) 54min
c) 48min
d) 36min


✔Answer
✔Solution
Correct Answer Is : 54min
Solution Is : Ration of rates of walking =A:B=2:3 Ratio of their time taken=A:B=3:2 Here, 2x=36min x=18min 3x=18*3=54min so, the time taken by A to cover that much distance is 54min
The ratio of ages of two persons in 5 : 9 and the age of one of them is greater than the other by 40 years. The sum of their ages in year is

a) 140
b) 180
c) 150
d) 160


✔Answer
✔Solution
Correct Answer Is : 140
Solution Is : Ratio of two persons = 5 : 9 Difference between their ages = 40 Let age of first person = 5x and second person = 9x According to the question 9x - 5x = 40, 4x = 40, x = 10 Age of first person = 5x = 5*10 = 50 Age of second persons = 9x = 9 * 10 = 90 Sum of ages of both the persons = ( 50+90) = 140
The average age of the boys in the class is twice the number of girls in the class. If the ratio of the boys and the girls in the class of 36 of 5:1, What is the total of the ages of the boys in the class?

a) 490 yr.
b) 420 yr.
c) 360 yr.
d) 196 yr.


✔Answer
✔Solution
Correct Answer Is : 360 yr.
Solution Is : Number of boys in the class =5/6*36=30 Number of boys in the class =36-30=6 Average age of boys =2*6=12 Total age of boys =12*30=360 yr.
A sum was divided among A, B and C. C got double than A, who got double than B. If the difference between the share of B and C was Rs 3675 , what was the sum?

a) 4900
b) 8575
c) 11025
d) 7350


✔Answer
✔Solution
Correct Answer Is : 8575
Solution Is : Let B got Rs x A got Rs 2x and C got Rs 4x According to the question 4x-x=3675 x=1225 Required sum=x+2x+4x=7x =7*1225=Rs 8575
The cost of making an article is divided between materials, labour and overheads in the ratio 3 : 4 : 1. If the material cost is 22.50₹, find the cost of the article ?

a) ₹100
b) ₹80
c) ₹60
d) ₹40


✔Answer
✔Solution
Correct Answer Is : ₹60
Solution Is : Let cost of article be x, Material : Labour : Overheads = 3 : 4 : 1 Cost of material = 22.50 3/( 3 + 4 + 1) x = 45/2 x = 45/2 * 8/3 = 60.
Divide 13,680 in three parts such that 1st part is 3/5 th of the third part and the ratio between 2 nd and 3 rd part is 4 : 7. How much is the first part?

a) 3780
b) 6300
c) 3600
d) 4800


✔Answer
✔Solution
Correct Answer Is : 3780
Solution Is : Let x , y ,z be 3 parts . Given x = (3/5) z ---> 5x = 3z y/z = 4 / 7 ---> 7y = 4z x + y +z = 13,680 --- ( eqn 1 ) x = 3z/5 y = 4z/7 Substitute value of x and y in equation 1 3z/5 + 4z/7 + z = 13,680 (21z + 20y + 35z ) / 35 = 13680 76 z = 13680 x 35 z = 13680 x 35 / 76 z = 6300 x = 3x 6300 / 5 x = 3,780

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