#### Delhi Police Exam Numerical Ability Study Material

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b) 875

c) 785

d) 758

Where, x is the distance of the train which has speed is 50 km

75X=50X+50 x 175,25X =5870 ,x=350 ,Distance Between A and B is X +(X+175)=350+(350+175)=875

b) 52%

c) 20%

d) 25%

12% of x = 72

100% of x = 72 X 100 /12=600 ,Pass marks = 20% of 600 + 30 = (600 x 20)/100 + 30

= 120 +30= (150x100)/600

Per cent pass marks = 25%

b) 15.00%

c) 28.00%

d) 25.00%

b) Rs. 1500

c) Rs. 1600

d) Rs. 1700

Average expenses of next 7 months = 1300

Saving of twetve months 2900

So, the total expenses of first 5 months = 6000

and total expenses of next 7 months = 9100

Sum of tweLve months= 15100

Saving of twelve months = 2900

Therefore, the total income of twelve months = 15100+ 2900

= 18000

Hence. the monthly income of a man = 12 = 1500

b) (15/33)

c) (11/39)

d) (17/39)

b) 560kg

c) 600kg

d) 640kg

1O8%of x X C + 118%of(1 000 -x) X C=114%of 1000 X C , 4000C=10 X C ,X=4000/10

Hence, required cuantity = 400kg

b) 20

c) 25

d) 30

and the selling price of an articte= 125% of 1500= 1875

Amount of tax (pay)= 75

Then net prof (1875 ? 75 ? 1500) = 300

Per cent prof1= (300x100)/1500=20%

b) 148

c) 149

d) 150

Hence, the required number

= 48 x n + 3, dvisble by 7

= 48 x 3 + 3 = 147 divisible by 7 Let n =3

b) 1008 *6/7 km

c) 189km

d) 378km

b) 1200

c) 960

d) 1152

Let the cost price of watch = x

(100? 25)%O f X =720

125 x720 = 1200

125% of x = 125X720/75 =1200